I need help pleaseeeeee

Mathematics

1 answer:

My name is Ann [436]2 years ago

5 0

I think it’s 18 x hope this helps

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Determine the values of k and p so that the solution is "All Reals" when solving for y:

Angelina_Jolie [31]

Answer:

The value of k is $\pm 9$ and The value of p is - 23

Step-by-step explanation:

Given equation as :

81 y - 17 = k² y + 6 + p

The equation has real solution ,

Now for real solution the equation have no solution

∵ The equation has no solution the ,

The coefficient of y must be equal

I.e 81 = k²

Or, k = $\sqrt{81}$

∴ k = $\pm 9$

Again , If the coefficient of y is same then the equation is written as

6 + p = - 17

or, p = - 17 - 6

or, p = - 23

Hence The value of k is $\pm 9$ and The value of p is - 23 Answer

6 0

2 years ago

Plzz help Solve for x x ÷3 3/10 =2 2/5

Svet_ta [14]

Answer:

$\huge\boxed{x=7\dfrac{23}{25}}$

Step-by-step explanation:

$x\div3\dfrac{3}{10}=2\dfrac{2}{5}\\\\\text{convert the mixed number to the impropper fraction}\\\\3\dfrac{3}{10}=\dfrac{3\cdot10+3}{10}=\dfrac{33}{10}\\\\2\dfrac{2}{5}=\dfrac{2\cdot5+2}{5}=\dfrac{12}{5}\\\\x\div\dfrac{33}{10}=\dfrac{12}{5}\\\\x\times\dfrac{10}{33}=\dfrac{12}{5}\qquad\text{multiply both sides by}\ \dfrac{33}{10}\\\\x\times\dfrac{10\!\!\!\!\!\diagup}{33\!\!\!\!\!\diagup}\times\dfrac{33\!\!\!\!\!\diagup}{10\!\!\!\!\!\diagup}=\dfrac{12}{5}\times\dfrac{33}{10}\\\\x=\dfrac{396}{50}$