Melea gallops her horse 0.5 miles in 1.25 minutes. How fast is the horse galloping?

I have no clue what it is

Orlov [11]

13.95+2.25+2.25+2.25+2.75+2.75+2.75= 28.95

6 0

3 years ago

Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:

Nataly_w [17]

We have that
tan(theta)sin(theta)+cos(theta)=sec(theta)
[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
[sin²(theta)/cos(theta)]+cos(theta)=sec(theta)

the next step in this proof
is write cos(theta)=cos²(theta)/cos(theta) to find a common denominator
so

[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)

{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)

remember that
sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok

the answer is the option B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.

6 0

3 years ago

Read 2 more answers

2.

victus00 [196]

Answer:

With a vertex (h, k) at (0, 3) and given that a = -3, then the equation of this parabola in vertex form is as follows:

y = a(x - h)2 + k

y = -3(x - 0)2 + 3

y = -3x2 + 3

Step-by-step explanation:

7 0

3 years ago

Find the value(s) of x where the tangent to the graph of y=e^5x is parallel to the

Alik [6]

Answer:

There are none.

Step-by-step explanation:

No calculus involved:

The line, in slope-intercept form, has equation $y=-10x+17$ , ie is always decreasing (easy to spot applying the definition)

Meanwhile, $y=e^{5x}$ is always increasing over its domain.

At no point the tangent will be decreasing.

Let's use calculus

We are to solve the equation $y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2$ which has no real solutions.

8 0

3 years ago

PLEASE HELPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OLga [1]

The set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

<h3>How to generate the numbers in the Collatz Conjecture</h3>

To start with, we make use of the following starting point:

Starting point = 1

The rule is given as:

If the last number is odd, multiply it by 3 and add 1.
If the last number is even, divide the number by 2.

1 is an odd number.

So, we use the first rule

So, we have:

1 * 3 + 1 = 4

4 is an even number.

So, we use the second rule

So, we have:

4/2 = 2

So, the first three numbers in the Collatz Conjecture are:

1, 4, 2

Using the given rules, we have:

1, 4, 2, 1, 4, 2, 1, 4, 2....

The above means that there is only one set of repeating numbers in the Collatz Conjecture.

Hence, the set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....