Question

What is the fifth term of the sequence generated by the formula below? an=n^3+n^2-9n-9

Answer 1

Answer:

$a_{5} = 96$.

Step-by-step explanation:

Given  : $a_{n} = n^{3} +n^{2} -9n -9$.

To find : What is the fifth term of the sequence .

Solution : We have given $a_{n} = n^{3} +n^{2} -9n -9$.

For n = 5

$a_{5} = 5^{3} +5^{2} -9(5) -9$.

Open the cubes and squares

$a_{5} = 125 + 25 - 45 -9$.

Add the terms

$a_{5} = 96$..

Therefore,  $a_{5} = 96$.

Answer 2

The correct answer is 96