The expression is (15+6) */* 3. This is because we add up all the costs to get the total, and divide the total by three because there are three friends splitting the cost.
Michael worked 4.5 hours. 65.75 - 36.50 = 29.25, therefore, Michael made $29.25 not including tips. 29.25/6.50 = 4.5
Answer:
q = log4 / log0.53
q = -2.189
Step-by-step explanation:
(0.53)^q = 4
Taking log of both sides!
q log 0.53 = log 4
q = log 4 / log 0.53
q = 0.602 / -0.275
q = - 2.189
This can be checked to confirm correctness.
Substituting q = -2.189
(0.53)^ -2.189 = 1/ 0.249
= 4.01 Proved!
(Note that the "1" is because of the negative sign)
The inclusion/exclusion principle states that
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That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).
Therefore,

will have the most elements when the sets

and

are disjoint, i.e.

, which would mean the most we can can in this case would be

(Note that

denotes the cardinality of the set

.)