Help me with this please #17
1 answer:
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Answer:
C. symmetric with respect to the origin
Step-by-step explanation:
A graph must pass the vertical line test to be called the graph of a function. No function will ever be symmetrical with respect to the x-axis, because that would mean it fails the vertical line test.
An even function is symmetrical about the y-axis. An even function has the characteristic that ...
f(-x) = f(x) . . . . an even function
An odd function is symmetrical about the origin. An odd function has the characteristic that ...
f(-x) = -f(x)
__
The given function is f(x) = -1/x. Then the value of f(-x) is ...
f(-x) = -1/-x = 1/x = -f(x)
The given function is an odd function, so is symmetrical about the origin.
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Answer:
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Step-by-step explanation:
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Hope it helps
Answer:
Step-by-step explanation:
x² + 2x = 6
Subtract both sides by 6.
x² + 2x - 6 = 0
ax²+bx+c=0
a=1, b=2, and c=-6
We can apply the quadratic formula.
Plug in the values.
Evaluate.
Answer:
Attached is the image of the solution . cheers
