Help me with this please #17
1 answer:
9514 1404 393
Answer:
C. symmetric with respect to the origin
Step-by-step explanation:
A graph must pass the vertical line test to be called the graph of a function. No function will ever be symmetrical with respect to the x-axis, because that would mean it fails the vertical line test.
An even function is symmetrical about the y-axis. An even function has the characteristic that ...
f(-x) = f(x) . . . . an even function
An odd function is symmetrical about the origin. An odd function has the characteristic that ...
f(-x) = -f(x)
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The given function is f(x) = -1/x. Then the value of f(-x) is ...
f(-x) = -1/-x = 1/x = -f(x)
The given function is an odd function, so is symmetrical about the origin.
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Answer:
C' (-4 , 2)
slope of new line = line "L" = -2
Step-by-step explanation:
C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3
C' (x,y)
x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)
y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)
C' (-4 , 2)
slope of new line = line "L" = -2
