Answer:
Step-by-step explanation:
Using the area model and standard algorithm, we have:
332 (tenths)
<u> × 21 </u>
332
<u> 664 </u>
<u> 6972 </u> tenths = 697.2
<u />
30 + 3 tenths
1 300 32 332
20 600 64 664
33.2 × 21 =<u> 30 </u> × <u> 1 </u> = <u> 30 </u>
Answer:
sum of terms: 55550
Explanation:
Here the number of terms:
1100 ÷ 11 = 100
Using the Formula:
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Answer:
Vertex - (2, -1)
Axis of Symmetry - x = 2
X intercept - (3,0) (1, 0)
Y intercept (0, 3)
Domain - (negative infinity, positive infinity)
Range - [-1, infinity)
Step-by-step explanation:
I graphed with desmos and found it.
Answer:
1) (6,2) (9,2) (3,8) (3,5)
2) (2,-5) (5,-5) (-1,-11) (-1,-8)
Step-by-step explanation:
For the first question, your reflecting over the x-axis into quadrant I, so you just need to make all the coordinates positive. The numbers stay the same - you just get rid of the negative signs. (6,2) (9,2) (3,8) (3,5)
For the second problem, you subtract 4 from the x-value, and 3 from the y-value.
(6,-2) becomes (2,-5)
(9,-2) becomes (5,-5)
(3,-8) becomes (-1,-11)
(3,-5) becomes (-1,-8)
