I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 SEE ATTACHED IMAGE.
 Using Heron's Formula we can find the area of the triangle.
 A = root (s (s-a) * (s-b) * (s-c))
 s = (a + b + c) / 2
 Where,
 s: semi-perimeter
 a, b, c: sides of the triangle
 Substituting values:
 s = (15 + 16 + 20) / 2
 s = 25.5
 s = 26
 The area will be:
 A = root (26 * (26-15) * (26-16) * (26-20))
 A = 130.9961832
 A = 130 u ^ 2 
Answer:
 The area of triangle ABC is:
 C.
 130 u ^ 2
 
        
             
        
        
        
Answer:
5.131 × 10¹⁴  Hz
Step-by-step explanation:
<u>Planck relation</u>

where:
- E = Energy of the photon (J).
- h = Planck's constant (J · s).
- f = frequency of light produced (Hz).
Given values:
- E = 3.4 × 10⁻¹⁹ J
- h = 6.626 × 10⁻³⁴ J · s
Substitute the given values into the formula and solve for f:






 
        
             
        
        
        
Answer:
50 is the intrest 550 os the amount
 
        
             
        
        
        
Answer:
140 m/s
Step-by-step explanation: