Answer:
<u>Point C at (-18/7)</u>
Step-by-step explanation:
Point A is at -6 and point B is at 2.
So, the distance between A and B = 2 - (-6) = 8
point C on the directed line segment from A to B on a number line such that the segment is partitioned in a ratio of 3:4.
Let the distance AC = x
∴ BC = 8 - x
AC : CB = 3 : 4
∴
Using cross multiplication
3 (8-x) = 4x
24 - 3x = 4x
24 = 7x
x = 24/7
So, Point C = -6 + 24/7 = -18/7
Point C at (-18/7)
Answer:
See below ~
Step-by-step explanation:
<u>Question 1</u>
<u>The missing angles</u>
- Both the unknown angles have the same value as the other two angles in the triangles are the same
- ∠(missing) = 180 - (72 x 2)
- ∠(missing) = 180 - 144
- ∠(missing) = 36°
⇒ The sides are <u>equal</u>
⇒ Angles are <u>not 90°</u>
⇒ It is a <u>rhombus</u>
<u></u>
<u>Question 2</u>
- The <u>diagonals</u> of the shape <u>bisect other</u> (Statement 1)
- NY = NW (given)
- XN = NZ (given)
- ∠XNY = ∠WXZ (vertically opposite angles)
- ΔXNY ≅ ΔWXZ (SAS)
- They form <u>two congruent triangles</u> (Statement 2)
- From these two statements, it is evident the figure is a <u>parallelogram</u>
A.) P(t) = P0exp(kt)
P(20/60) = 40 exp(20k/60)
80 = 40 exp(k/3)
exp(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = exp(8k) = exp(8(3ln(2)) = exp(24ln(2)) = exp(16.6355) = 16777216 cells / hour
e.) P(t) = 40(2)^3t; t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
D.
x-intercept = 5
y-intercept = 15