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larisa86 [58]
3 years ago
11

HURRY! Match each function with the correct inverse of the function. BEST & FASTEST ANSWER GETS BRAINIEST ANSWER!!!!!!!!!

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
2 1 3 6 5 hope I helped
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A tent is in the shape of the picture shown below, calculate the total of the tent, ROUND TO THE NEAREST HUNDREDTH
Taya2010 [7]

Answer: The volume of the tent is 293.33 ft.

Explanation: 11 x 10 x 8 = 880

The formula for the volume of a right rectangular pyramid is lwh/3.

880/3 = approximately 293.33

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2 years ago
2 fractions between 3/5 and 4/5
Tasya [4]
Convert the fractions to decimals:

3/5=0.6
4/5=0.8

You have to find 2 fractions between these 2 numbers. You could pick anything.

7/10= 0.7 = less than 0.8 but greater than 0.6

75/100=0.75 = less than 0.8 but greater than 0.6

Hope this helps

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3 years ago
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Step-by-step explanation:

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George has a small coin collection. He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a fl
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3 0
3 years ago
A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1
kvasek [131]

Answer:

CI=\{-0.2941,-0.0337\}

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is \displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2} where \hat{p}_1 and n_1 are the sample proportion and sample size of the first sample, and \hat{p}_2 and n_2 are the sample proportion and sample size of the second sample.

We see that \hat{p}_1=\frac{87}{249}\approx0.3494 and \hat{p}_2=\frac{58}{113}\approx0.5133. We also know that a 98% confidence level corresponds to a critical value of z^*=2.33, so we can plug these values into the formula to get our desired confidence interval:

\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

5 0
2 years ago
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