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larisa86 [58]
3 years ago
11

HURRY! Match each function with the correct inverse of the function. BEST & FASTEST ANSWER GETS BRAINIEST ANSWER!!!!!!!!!

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
2 1 3 6 5 hope I helped
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Determine the volume of the rectangular prism.<br>​
Flauer [41]

Answer:

<h2><u>50 ft³</u></h2>

Step-by-step explanation:

We know the formula for a rectangular prism is length × width × height

We also know all the sides so we can rewrite the formula replacing variables.

The length is 8, the width is 2\frac{1}{2} and the height is 2\frac{1}{2}

8 × 2\frac{1}{2} × 2\frac{1}{2}

Multiply which ever way is easy for you. I am just multiplying from left to right.

8 × 2\frac{1}{2} = 20

20 × 2\frac{1}{2} = 50

Now we get 50. Before we put our answer as 50, there are two more steps.

First we need to add the measurement unit which is feet or ft

We also need to add ³ since it is volume

<u>50 ft³ is our final answer</u>

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3 years ago
A very, very hungry guy goes to a fast food place and orders 2 chicken sandwiches
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Answer:

Step-by-step explanation:

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What is the change in elevation from -6 km to -14 km?
Feliz [49]

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-8 km

Step-by-step explanation:

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7. Find the slope. Make sure to reduce.
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The slope is zero

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Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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