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k0ka [10]
3 years ago
12

Which of the segments below is a secant?

Mathematics
2 answers:
denpristay [2]3 years ago
8 0

Answer:

C.HJ

Step-by-step explanation:

mamaluj [8]3 years ago
5 0

b) HJ

......................

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Chukwu, Abdul and kunle are to share $142, such that Abdul gets $11.00 less than Chukwu and $7.00 more than Kunle. How much is C
Elena-2011 [213]

Answer:

Chukwu's share is of $57.

Step-by-step explanation:

This question is solved by a system of equations.

I am going to say that:

Chukwu's share is x.

Abdul's share is y.

Kunle's share is z.

Chukwu, Abdul and kunle are to share $142

This means that x + y + z = 142

Abdul gets $11.00 less than Chukwu

This means that:

y = x - 11

$7.00 more than Kunle.

This means that:

y = z + 7

So

z = y - 7

z = x - 11 - 7

z = x - 18

How much is Chukwu's share?

We want to find x, so:

x + y + z = 142

x + x - 11 + x - 18 = 142

3x - 29 = 142

3x = 171

x = \frac{171}{3}

x = 57

Chukwu's share is of $57.

7 0
4 years ago
Revenue from Monorail Service, Las Vegas In 2005 the Las Vegas monorail charged $3 per ride and had an average ridership of abou
Karolina [17]

Answer:

A)The required linear demand equation ( q ) = -4500p + 41500

B) $4.61

   $95680.55

C) No it would not have been possible by charging a suitable price

Step-by-step explanation:

<u>A)  find the linear demand equation</u>

given two points ; ( 3, 28000 ) and ( 5, 19000 )

slope ( m ) = ( y2 - y1 ) / ( x2 - x1 )

                 = ( 19000 - 28000 ) / ( 5 - 3 )  = -4500

slope intercept is represented as ; y = mx + b

where y( 28000) = -4500(3) + b

  hence b = 41500  

hence ; y = -4500x + 41500

The required linear demand equation ( q ) = -4500p + 41500   ----- ( 1 )

p = price per ride

<u>B ) Determine the price the company should charge to maximize revenue from ridership  and corresponding daily revenue</u>

Total revenue ( R ) = qp

                               = p ( -4500p + 41500 )

  hence R = -4500p^2 + 41500p  ------ ( 2 )

To determine the price that should maximize revenue from ridership we will equate R = -4500p^2 + 41500p  to a quadratic equation R(p) = ap^2 + bp + c

where a = -4500 ,  b = 41500 , c = 0

hence p = -\frac{b}{2a}  = - \frac{41500}{2(-4500)} =  4.61

$4.61 is the price the company should charge to maximize revenue from ridership

corresponding daily revenue = R = -4500p^2 + 41500 p

where p = $4.61

hence R = -4500(4.61 )^2 + 41500(4.61) = $95680.55

C) No it would not have been possible by charging a suitable price

5 0
3 years ago
0.5 as a fraction in lowest term
Nadusha1986 [10]

Seriously?

.5 = 5/10 = 1/2 reduced

3 0
3 years ago
Read 2 more answers
Please answer give it too me now
OverLord2011 [107]

Answer:

5/3

Step-by-step explanation:

HTH :)

8 0
3 years ago
Solve for x 3.8 4.8 5.8 6.8
Bas_tet [7]

Answer:

Step-by-step explanation:

Similar

\frac{5}{3}=\frac{8}{x}\\\\5*x=8*3\\\\x =\frac{24}{5}

x=4.8

7 0
3 years ago
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