Answer:
the answer is c.
Step-by-step explanation:
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus
Selections 2, 3, 5, 6 are polynomials.
1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).
Answer:
<em>£ 449.20</em>
Step-by-step explanation:
We have to reduce 465.98 by 3.6%
Firstly, lets convert the percentage to decimal by dividing by 100. So we have:
3.6/100 = 0.036
Lets find 3.6% of 465.98
That is:
0.036 * 465.98 = 16.77528
This is the "LESSENED" amount. So the final amount would be:
465.98 - 16.77528 = 449.20472
<em>Rounding to 2 decimal places, £ 449.20</em>
2(3x + 5) (x - 1)
This is done through factoring 2 out of the equation first...
2(3x^2 + 2x -5)
And then cross multiplying it