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Phantasy [73]
3 years ago
10

Is this graph a function or not a function

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Do a vertical line test.

First, put your pencil or ruler up against the screen.

Move it down the graph and if there are two points in one x point, it is not a function. For example, look at 0, 3 and 0, -2.5. They share the same x point.

Therefore, it is not a function.

kiruha [24]3 years ago
5 0

Answer:

In the graph of a circle, we can easily draw a straight vertical line passing through its center. This will hit the top and the bottom of the shape. Since this line hits two points, a circle's graph is not a function. We can also observe the equation of a circle.

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Use the graph to find the slope. What is the runners speed?
Murrr4er [49]

The formula for the slope is m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{20-10}{2-1}

m=\frac{10}{1}

m=10

Hope this helps.

頑張って!

3 0
3 years ago
At 1 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
Evgen [1.6K]
<span>The distance between the ships is changing at a rate of 21.393 km/h

</span><span>Step 1: First, you must draw an image to help better understand the problem 
</span>

The reason that ship A is moving -35km/h is because ship B acts as an "origin" and as things move closer to the "origin" they become negative and as things move away from the "origin" they become positive.

We know that the rate of Ship A is expressed as <span><span><span>dA</span><span>dt</span></span>=−35</span> and the rate of Ship B is expressed as <span><span><span>dB</span><span>dt</span></span>=25</span>

Step 2: We want to figure out how many km Ship A and Ship B traveled in 4 hours

<span>ShipA:−35<span><span>km</span>h</span>⋅4hr=−140km</span>

Now if we take this <span>−140km</span> and add it to the <span>150km</span> we can see that Ship A is now only <span>10km</span> away from where Ship B began

<span>ShipB:25<span><span>km</span>h</span>⋅4hr=100km</span>

This means that Ship B is now <span>100km</span> from where it originally started

We can now redraw our information

Step 3: We must use the Pythagorean Theorem to find the third side of the triangle

<span><span>x2</span>+<span>y2</span>=<span>z2</span>→<span>102</span>+<span>1002</span>=<span>z2</span></span>

<span>z=<span>√<span><span>102</span>+<span>1002</span></span></span></span>

Step 4: Now that we know z, we must differentiate the original equation in order to find the rate at which z in changing

<span><span>x2</span>+<span>y2</span>=<span>z2</span>→2x<span><span>dx</span><span>dt</span></span>+2y<span><span>dy</span><span>dt</span></span>=2z<span><span>dz</span><span>dt</span></span></span>

We can simplify by canceling out the 2's

<span>x<span><span>dx</span><span>dt</span></span>+y<span><span>dy</span><span>dt</span></span>=z<span><span>dz</span><span>dt</span></span></span>

Step 5: Write down all the information and then plug into equation

<span>x=10and<span><span>dx</span><span>dt</span></span>=−35</span>
<span>y=100and<span><span>dy</span><span>dt</span></span>=25</span>
<span>z=<span>√<span><span>102</span>+<span>1002</span></span></span>and<span><span>dz</span><span>dt</span></span>=?</span>

Now plug in the information

<span>x<span><span>dx</span><span>dt</span></span>+y<span><span>dy</span><span>dt</span></span>=z<span><span>dz</span><span>dt</span></span></span>

<span>10<span>(−35)</span>+100<span>(25)</span>=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>−350+2500=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>2150=<span>√<span><span>102</span>+<span>1002</span></span></span><span><span>dz</span><span>dt</span></span></span>

<span>21.393=<span><span>dz</span><span>dt</span></span></span>

The distance between the ships are increasing at a rate of 21.393 km/h

8 0
3 years ago
How to solve equations with the substitution method
Paul [167]

Answer:

In a system, the substitution method is one of the 3 main ways to solve a system and can be very efficient at times.

<u>Skills needed: Systems, Algebra</u>

Step-by-step explanation:

1) Let's say we are given two equations below:

  y=4x \\ 4x-5y=-32

  We can use substitution here by substituting in for y in the second equation.   This means we put in 4x for y in the 2nd equation so we only have x variables in the equation, allowing us to solve for x.

2) Solving it out:

1) 4x-5(4x)=-32 \\ 2) 4x-20x=-32 \\3) -16x=-32 \\4)x=2\\5)y=4x = 4(2) = 8 \\ 6)y=8

We essentially substitute in that value as seen in step 1. Steps 2 and 3 are just simplifying the left side and allowing for us to solve. Step 4 is where we divide by -16 on both sides to solve for x. Step 5 and 6 show us solving for y using the value for x. We get x=2,y=8

5 0
2 years ago
Read 2 more answers
Adhy, Ben and Clayson shared a bag of chocolates. The ratio of Adhy's share to Ben's share is 3:4 while
Ira Lisetskai [31]

Answer:   33

<u>Step-by-step explanation:</u>

The ratio of Adhy's to Ben's is 3:4 so let

Adhy = 3x

Ben = 4x

Since Ben = Adhy + 9

then   4x   =    3x    + 9

-->        x    =  9

So, Adhy = 3x  = 3(9)   = 27

     Ben   = 4x   = 4(9)   = 36

*************************************************************

The ratio of Ben's to Clayson's is 3:5

How do we get Ben's ratio of 3 equal to 36? <em>by multiplying by 12</em>

Ben  :  Clayson

<u>3 x 12</u>    <u>5 x 12</u>

 36          60

So, Clayson = 60

***********************************************************

The difference between Adhy and Clayson is:

Clayson - Adhy

   60     -    27    = 33

3 0
3 years ago
For what values of a does the equation a+x= 1+xa^2 have no solution?
Anton [14]

Answer:

We have the equation

a+x= 1+xa^2

we leave the terms with x on the left side of the equation and the independent terms on the right side.

x-xa^2=1-a\\(1-a^2)x=1-a\\

resolving for x we have that

x=\frac{1-a}{1-a^2}

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when 1-a^2=0\\1=a^2\\a=\pm1

Then, for a=\pm1 the equation hasn't solution

7 0
3 years ago
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