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Dima020 [189]
3 years ago
5

A car travel the distance of D equals 450 km for T equals 4.4 hours at a constant rate. What is the speed of the car in kilomete

rs per hour
Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

102.3 kilometers per hour

Step-by-step explanation:

A car travel the distance of D equals 450 km for T equals 4.4 hours at a constant rate. What is the speed of the car in kilometers per hour

The formula to calculate Speed = Distance (Kilometers)/ Time(hours)

The speed of the car = 450km/4.4 hours

102.27272727 kilometers per hour

Approximately = 102.3 kilometers per hour

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Smoothies weren't cutting it so we went to Red Robin to order a burger. Our bill was $5.79. Avon has a 5.25% tax and our
ahrayia [7]

Answer:

$6.96

Step-by-step explanation:

5.25% of 5.79

5.79 × 5.25/100 = $0.303975 or $0.30

15% of 5.79

5.79 × 15/100 = $0.8685 or $0.87

total

$5.79 + $0.30 + $0.87 = $6.96

4 0
3 years ago
Jim saw that other bank offered the same rates but compounded the interest more often. Consider if he still put $15,000 into a s
Kazeer [188]

Compound interest is the addition of interest on the interest of the principal amount.

<h3>What is compound interest?</h3>

Compound interest is the addition of interest on the interest of the principal amount. It is given by the formula,

A = P(1+ \dfrac{r}{n})^{nt}

As it is given that the principal amount is $15,000; while the rate of interest is 2.8%, and the amount is invested for a period of 5 years.

A.) When the interest is charged weekly,

As we know that there are 52 weeks in a year, therefore, n = 52, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{52})^{52 \times 5}\\\\A = \$17,253.46

B.) When the interest is charged daily,

As we know that there are 365 days in a year, therefore, n = 365, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{365})^{365 \times 5}\\\\A = \$19,554.55

C.) When the interest is charged Continuously,

As we know that the formula for continuous compounding is given as,

A = Pe^{rt}

Substitute the values, we will get,

A = 15000 \times (e^{0.024 \times 5})\\\\A= \$16,912.45

D.) When the interest is charged Monthly,

As we know that there are 12 months in a year, therefore, n = 12, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{12})^{12\times 5}\\\\A = \$15211.23

E.) When the interest is charged Semi-annually,

As we know that the interest is charged Semi-annually, therefore, n = 2, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{2})^{2\times 5}\\\\A = \$17,237.36

F.) When the interest is charged Quarterly,

As we know that the interest is charged Quarterly, therefore, n = 4, substitute the values,

A = P(1+ \dfrac{r}{n})^{nt}\\\\A = 15000(1+ \dfrac{0.028}{4})^{4\times 5}\\\\A = \$17,245.7

Learn more about Compound Interest:

brainly.com/question/25857212

4 0
3 years ago
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Answer:

92

Step-by-step explanation:

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3 years ago
Estimate each percent 19% of $53
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19 percent of 53 is 10.07
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4 years ago
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Which of the following best represents the solution set to - 5(x+3) &gt; - 3x + 5
love history [14]

Answer:

D.

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Step-by-step explanation:

- 5(x+3) > - 3x + 5

- 5x - 15 >  - 3x + 5

- 5x + 3x > 5 + 15

- 2x > 20

x > \frac{20}{ - 2}

x >  - 10

6 0
3 years ago
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