Answer:
a
b
![P( X \ge 6 )= 0.4516](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%20%206%20%29%3D%20%200.4516%20)
c
![P( X < 4 )= 0.12694](https://tex.z-dn.net/?f=P%28%20X%20%3C%20%204%20%29%3D%20%200.12694)
Step-by-step explanation:
From the question we are told that
The population proportion is p = 0.53
The sample size is n = 10
Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly five is mathematically represented as
=>
=>
Generally the probability that the number of U.S. adults who have very little confidence in newspapers is at least six is mathematically represented as
![P( X \ge 6 )= P( X = 6) + P( X = 7) + P( X = 8) + P( X = 9) + P( X = 10)](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%20%206%20%29%3D%20%20P%28%20X%20%20%3D%206%29%20%2B%20%20P%28%20X%20%20%3D%207%29%20%2B%20%20P%28%20X%20%20%3D%208%29%20%2B%20%20P%28%20X%20%20%3D%209%29%20%2B%20%20P%28%20X%20%20%3D%2010%29)
=> ![P( X \ge 6 )= [^{10}C_6 * [0.53]^6 * (1- 0.53)^{10-6}] + [^{10}C_7 * [0.53]^7 * (1- 0.53)^{10-7}] + [^{10}C_8 * [0.53]^8 * (1- 0.53)^{10-8}] + [^{10}C_9 * [0.53]^9 * (1- 0.53)^{10-9}] + [^{10}C_{10} * [0.53]^{10} * (1- 0.53)^{10-10}]](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%20%206%20%29%3D%20%20%5B%5E%7B10%7DC_6%20%2A%20%20%5B0.53%5D%5E6%20%2A%20%20%281-%200.53%29%5E%7B10-6%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_7%20%2A%20%20%5B0.53%5D%5E7%20%2A%20%20%281-%200.53%29%5E%7B10-7%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_8%20%2A%20%20%5B0.53%5D%5E8%20%2A%20%20%281-%200.53%29%5E%7B10-8%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_9%20%2A%20%20%5B0.53%5D%5E9%20%2A%20%20%281-%200.53%29%5E%7B10-9%7D%5D%20%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%5B0.53%5D%5E%7B10%7D%20%2A%20%20%281-%200.53%29%5E%7B10-10%7D%5D)
=> ![P( X \ge 6 )= [0.227] + [0.1464] + [0.0619] + [0.0155] + [0.00082]](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%20%206%20%29%3D%20%20%5B0.227%5D%20%2B%20%20%5B0.1464%5D%20%2B%20%20%5B0.0619%5D%20%2B%20%20%5B0.0155%5D%20%2B%20%5B0.00082%5D)
=> ![P( X \ge 6 )= 0.4516](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%20%206%20%29%3D%20%200.4516%20)
Generally the probability that the number of U.S. adults who have very little confidence in newspapers is less than four is mathematically represented as
![P( X < 4 )= P( X = 3) + P( X = 2) + P( X = 1) + P( X = 0)](https://tex.z-dn.net/?f=P%28%20X%20%3C%20%204%20%29%3D%20%20P%28%20X%20%20%3D%203%29%20%2B%20%20P%28%20X%20%20%3D%202%29%20%2B%20%20P%28%20X%20%20%3D%201%29%20%2B%20%20P%28%20X%20%20%3D%200%29)
=> ![P( X < 4 )= [^{10}C_3 * 0.53^3 * (1- 0.53)^{10-3}] + [^{10}C_2 * 0.53^2 * (1- 0.53)^{10-2}] + [^{10}C_1 * 0.53^1 * (1- 0.53)^{10-1}] + [^{10}C_0 * 0.53^0 * (1- 0.53)^{10-0}]](https://tex.z-dn.net/?f=P%28%20X%20%3C%20%204%20%29%3D%20%20%5B%5E%7B10%7DC_3%20%2A%20%200.53%5E3%20%2A%20%20%281-%200.53%29%5E%7B10-3%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_2%20%2A%20%200.53%5E2%20%2A%20%20%281-%200.53%29%5E%7B10-2%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_1%20%2A%20%200.53%5E1%20%2A%20%20%281-%200.53%29%5E%7B10-1%7D%5D%20%2B%20%20%5B%5E%7B10%7DC_0%20%2A%20%200.53%5E0%20%2A%20%20%281-%200.53%29%5E%7B10-0%7D%5D%20)
=> ![P( X < 4 )= 0.09051 + 0.03 + 0.0059 + 0.000526](https://tex.z-dn.net/?f=P%28%20X%20%3C%20%204%20%29%3D%20%200.09051%20%20%2B%20%200.03%20%2B%20%200.0059%20%2B%20%200.000526)
=> ![P( X < 4 )= 0.12694](https://tex.z-dn.net/?f=P%28%20X%20%3C%20%204%20%29%3D%20%200.12694)
Answer:
40/s
Step-by-step explanation:
Number of granola boxes = 5
Number of granola per box = 8
Total granolas = 8 * 5 = 40 granola bars
Number of students = s
If each students takes equal share : Number if granola bars taken by each :
Total number of granola bars / number of students
= 40 ÷ s
40/s
Ok, i understand now. Your answer should be G.
If you ever have a graphing question got to desmos.com
it helps me a lot. If you plug in any equation, like this one, life will be even easier. lol
The answer is c 143.ok bye
Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>