Answer:
Plates are 2.80 Dollars and cups are 1.40 dollars
Step-by-step explanation:
Cups = c
Plates = p
6p + 5c = 23.80 ==> multiply by 6 ==> 36p + 30c = 142.80
7p + 6c = 28.00 ==> multiply by 5 ==> 35p + 30c = 140.00
Now use algebra to have the 30c be on one side and the rest on the other:
36p + 30c = 142.80 | -36p
30c = 142.80 - 36p
35p + 30c = 140.00 | -35p
30c = 140.00 - 35p
Now set them equal to each other about the 30c:
142.80 - 36p = 140.00 - 35p
Use algebra to solve for p:
142.80 - 36p = 140.00 - 35p | +36p
142.80 = 140.00 + p | - 140
2.80 = p
Go back to one of the "30c" equations and plug in the value for p:
30c = 140 - 35p
30c = 140 - 35(2.80)
30c = 140 - 98
30c = 42 | /30
c = 42/30
c = 1.4
Answer:
Step-by-step explanation:
Given
Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height
Suppose they have same mass and radius
time Period is given by
,where h=height of release
a=acceleration

Where I=moment of inertia
a for hoop


a for Uniform solid cylinder


a for spherical shell


a for Uniform Solid


time taken will be inversely proportional to the square root of acceleration




thus first one to reach is Solid Sphere
second is Uniform solid cylinder
third is Spherical Shell
Fourth is hoop
The answer of the next term is 31
First, you would have to do 11x + 3x Since you're combining like terms.
Now your problem is 14x + 40 = -24
Now you would do 40 - -24 which is now 40+24 and equal to 64.
Now you divide 14 by 64 and you get 4.5
Complete question is;
Mia is tracking her savings account balance. She knows the equation y = 8000p^(t) can be used to find her balance y in any year t, but she can't remember what p represents. Her balance 3⅔ years after opening her account, is $9,905.54. What is the value of p?
Answer:
p = 1.06
Step-by-step explanation:
We are told that the equation y = 8000p^(t) can be used to find her balance y in any year t.
Now, we are given t = 3⅔ = 11/3 years
Also, we are given balance after 11/3 years as;
y = $9,905.54
Thus;
Plugging the relevant values into y = 8000p^(t), we have;
9,905.54 = 8000p^(11/3)
p^(11/3) = 9905.54/8000
p = (9905.54/8000)^(3/11)
p = 1.06