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kondaur [170]
3 years ago
14

The sum of two numbers, x and y, is 12. The difference of x and two times y is 6. What are the values of x and y?

Mathematics
2 answers:
ikadub [295]3 years ago
5 0
We write to expressions since there are two unknown here which is x and y. The first expression is the <span>sum of two numbers, x and y, is 12.

x + y = 12

The second expression is that the </span><span>difference of x and two times y is 6.

x -2y = 6

Therefore, the values of x and y are 10 and 2.</span>
netineya [11]3 years ago
5 0

Answer:

The values of x= 10 and y = 2

Step-by-step explanation:

Assume x>y

The first statement states that sum of two numbers,  x and y, is 12

then, we can write this statement in algebraic expression:

x+y =12   ...[1]

The second statement states that the difference of x and two times y is 6.

we can write it as :

x -2y =6    ....[2]

Now, subtracting equations, we  will eliminate x leaving an equation in y that we can solve:

⇒ [1]-[2] gives

(x+y)-(x-2y) = 12-6

or

x+y-x+2y = 6

On simplify we get;

3y=6 or

y=2

Now, substitute the value of y=2 in equation [1] we get;

x+2=12

On simplify, we get;

x =10

therefore, the values of  x and y are, 10 and 2.




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Mice21 [21]

Answer:

\displaystyle -x^3+10x^2-48x+64

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

x= 4+4i\text{ and }  x = 2

As well as a <em>y-</em>intercept of 64.

By the Complex Root Theorem, if <em>a</em> + <em>b</em>i is a root, then <em>a</em> - <em>b</em>i is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

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Where <em>a</em> is the leading coefficient and <em>p</em> and <em>q</em> are the zeros. More factors can be added if necessary.

Substitute:

P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}

Hence:

P(x)=a(x-2)(x^2-8x+32)

Lastly, we need to determine <em>a</em>. Since the <em>y-</em>intercept is <em>y</em> = 64, this means that when <em>x</em> = 0, <em>y</em> = 64. Thus:

64=a(0-2)(0^2-8(0)+32)

Solve for <em>a: </em>

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Our factored polynomial is:

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Finally, expand:

\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}

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<h3>How to determine recursive formula of a geometric sequence?</h3>

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