<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>
We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').
First, we need to add up all the percentages to make sure we have 100%.
25.5% + 0.03% = 25.53%
This means that 74.47% of the students chose something other than basketball or soccer.
The amount of students you stated there were was 2553.
25.5% of 2553 is 651 students and
0.03% is 8 students.
Now, we divide 651 by 8 to determine the amount of times over basketball was chosen.
651 ÷ 8 = 81
Basketball was chosen 81 times over again compared to soccer.
To find how much more times basketball was chosen, subtract 8 from 651
651 - 8 = 643
Basketball was chosen 643 times more than soccer.
Answer:
8
Step-by-step explanation:
Recall the formula for the population mean of a data set:

We already know that μ is 6 and the sum is 48. Substitute:

Divide both sides by 48:

Reciprocal of both sides:

Thus, there are 8 scores in the population size.
And we're done!
Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 + 1 * 0.3050.60 + 0.305 = 0.9050.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 + 2 * 0.3050.60 + 0.61 = 1.210.60 - 0.61 = -0.01
Answer: The side length of the square-shaped park is 120 meters.
Here we know that:
Here we Ann has two plots of land, one square and other triangular.
We know that the triangular one has an area of 32,500 m^2
And we also know that the total area is equal to 76,600 m^2
Then the area of the square plot will be equal to the difference between the total area and the area of the triangular plot.
area of the square plot = 76,600 m^2 - 32,500 m^2
Now, also remember that for a square of side length x, the area is given by:
A = x^2
Replacing that in the above equation we get:
x^2 = 76,600 m^2 - 32,500 m^2
Now we want to solve this for x, the side length of the square-shaped park.
First, let's solve the difference in the right side:
x^2 = 44,100 m^2
Now we can apply the square root in both sides to get:
√x^2 = √(44,100 m^2)
x = 210 m
The side length of the square-shaped park is 120 meters.
Step-by-step explanation: