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3 years ago

Please help. If you could put your work in the answer that would Be greatly appreciated.

Mathematics

1 answer:

AleksandrR [38]3 years ago

6 0

Answer:

38°

because it is equal.

GJ=21

JH=21

GJ=JH

∠GFJ =∠HFJ

∠GFJ =38°

∠HFJ=38°

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Explain how you got the answer

Gnoma [55]

Answer:

$\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }$

Step-by-step explanation:

<u><em>Given equation is</em></u>

$x^2 + y^2 -6x-6y -42 = 0$

Adding 42 to both sides

$x^2 + y^2 -6x-6y = 42\\$

Completing squares

$x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42$

Adding (3)² => 9 and (3)² => 9 to both sides

$(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2 (y-3)^2 = (2{\sqrt{15})^2}$

Comparing it with $(x-h)^2+(y-k)^2 = r^2$ where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = $2\sqrt{15}$

7 0

3 years ago

It takes 2 minutes to fill a tank with 16 gallons of gasoline.

Olin [163]

Answer:

and the question is...

Step-by-step explanation:

5 0

3 years ago

I need help with 10,11,12

pshichka [43]

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3 years ago

Read 2 more answers

Simplify -x(4x^2 − 6x + 1)

12345 [234]

Answer:

$-4x^3+6x^2-x$

Step-by-step explanation:

1. Distribute the X across the equation: $-x(4x^2)=-4x^3\\$

2. $-x(-6x)=6x^2$

3. $-x(1)=-x$

3. $-4x^3+6x^2-x$

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2 years ago

A long distance runner does a first lap around a track in exactly 50 seconds.As she tires.Each subsequent lap takes 20% longer t

madreJ [45]

Answer:

182 seconds

Step-by-step explanation:

Given:

Time taken for first lap is 50 seconds and each subsequent lap takes 20% longer than previous

Solution:

Time taken for first lap = 50 sec

For second lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 50 sec

second lap = 50 + 20% of 50

second lap $=50+(\frac{20}{100}\times 50)$

second lap $= 50 + 10$

second lap $= 60\ sec$

For third lap

Each subsequent lap takes 20% longer than previous

Previous lap time = 60 sec

Third lap = 60 + 20% of 60

$Third\ lap = 60 + (\frac{20}{100}\times 60)$

$Third\ lap = 60+2\times 6$

$Third\ lap = 60+12$

$Third\ lap = 72\ sec$

Time taken for 3 laps is equal to sum of all three laps time.

$Tiem\ taken\ for\ 3\ lap = 50+60+72$

$Tiem\ taken\ for\ 3\ lap = 182\ sec$

Therefore, it takes 182 seconds (3 min, 2 seconds) to run three laps

6 0

3 years ago