Answer:
No, because the sides lengths are not proportional.
Step-by-step explanation:
<h3>What is the SAS similarity theorem ?</h3>
By definition, two triangles are similar if all their corresponding angles are congruent and their corresponding sides are proportional.
<h3>What is the AA similarity theorem ?</h3>
If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.
- They both have an angle of 70°
- This lies between sides of 6/9 and 9/18 respectively for the triangles
- 6/9 = 2/3 and 9/18 = 1/2
- Hence, the sides are not proportional
- They are not similar
Answer:
Step-by-step explanation:
Let x be the speed of first ferry.
Then the speed of second slower ferry is x-5 (since 5 miles per hour slower)
Time taken by first ferry = distance/speed = 
Time taken by second ferry = 
Since second ferry starts one hour early, difference in times is 1 hour.

Speed cannot be negative.
Hence answer is speed of the first ferry = 18.5 mph
and second ferry i.e. slower ferry is = 13.5 mph
It is -2/3
I gotchu don’t worry !
Answer:
The angles are related by Snell's Law of refraction.
Step-by-step explanation:
When light is incident on a medium at an angle this angle is known as angle of incidence and it undergoes refraction in the medium at an angle meaning that it deviates from it's normal path this angle of deviation measured with respect to normal is known as angle of refraction and are related by Snell's Law as under

here
is the refractive index of material of lens and
is the refractive index of air equaling 1
First we dra a triangle:
To prove that the triangles are similar we have to do the following:
Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

With this we conclude that traingles BCD and ACD are both similar to triangle ABC, and by the transitivity property of similarity we conclude that:

Now that we know that both triangles are similar we can use the following proportion:

this comes from the fact that the ratios should be the same in similar triangles.
From this equation we can find h:
![\begin{gathered} \frac{h}{x}=\frac{y}{h} \\ h^2=xy \\ h=\sqrt[]{xy} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7Bh%7D%7Bx%7D%3D%5Cfrac%7By%7D%7Bh%7D%20%5C%5C%20h%5E2%3Dxy%20%5C%5C%20h%3D%5Csqrt%5B%5D%7Bxy%7D%20%5Cend%7Bgathered%7D)
Plugging the values we have for x and y we have that h (that is the segment CD) has length:
![\begin{gathered} h=\sqrt[]{8\cdot5} \\ =\sqrt[]{40} \\ =\sqrt[]{4\cdot10} \\ =2\sqrt[]{10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%3D%5Csqrt%5B%5D%7B8%5Ccdot5%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B40%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B4%5Ccdot10%7D%20%5C%5C%20%3D2%5Csqrt%5B%5D%7B10%7D%20%5Cend%7Bgathered%7D)
Therefore, the length of segment CD is: