How to find distance on a triangle like the diagonal part with the Phyhagorean Theorem?
1 answer:
<em>H</em><em>2</em><em>+</em><em>P</em><em>2</em><em>+</em><em>B</em><em>2</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>
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Answer:
c
Step-by-step explanation:
Use Pi, 3.14. Divide the Diameter by 3.14 and you should get your answer. That's all I know.