Answer:
|Z| = |-1.36| < 1.645 at 0.1 level of significance
The null hypothesis is accepted
A manufacturer of banana chips are filling machine works correctly at the mean 449
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of the Population(μ) = 449
The Standard deviation of the population(σ) = 22
size of the sample 'n' = 36
mean of the sample(x⁻) = 444
Given the level of significance(α) = 0.1
Critical value Z = 1.645
<u><em>Step(ii):</em></u>-
<em>Null hypothesis</em>:H₀:
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449.0
(μ) = 449
<em>Alternative Hypothesis</em>:H₁: (μ) ≠ 449
Test statistic
![Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } } \\= \frac{444-449}{\frac{22}{\sqrt{36} } }](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7Bx%5E%7B-%7D%20-mean%7D%7B%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20%5C%5C%3D%20%5Cfrac%7B444-449%7D%7B%5Cfrac%7B22%7D%7B%5Csqrt%7B36%7D%20%7D%20%7D)
= -1.36
<em>Final answer:-</em>
|Z| = |-1.36| < 1.645 at 0.1 level of significance
The null hypothesis is accepted
A manufacturer of banana chips are filling machine works correctly at the mean 449