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3 years ago

What is Ed qqqqqqqqqqqqqqqqqqqqq

Mathematics

1 answer:

Darina [25.2K]3 years ago

8 0

Answer:

ED= 13

Step-by-step explanation:

The chord ED is intersected by JG. JG and JF are equivalent. Their equivalency comes from the center of the circle. It splits ED in half.

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Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes:

swat32

Answer:

0.615

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

i.e $P(\text{Morning }|\text{ Junior})$

We know that,

$P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}$

So,

$P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}$

Putting the values from the table,

$\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615$

3 0

2 years ago

How do I solve this problem using the substitution method x-3y=4 4x-2y=26

Nastasia [14]

Top 1. Substitute 3y on both sides of the equation.
Bottom 2. Substitute 2y on both sides of the equation

3y and 2y cancel

Divide x by 4 and 26 by 4.

Is there die points on a graph or decimal?

I have not done this for years but there is many calculators that can show you step by step online. I recommend using these

5 0

2 years ago

Read 2 more answers

See image attached below keeeeeeeeeeeeeeeeeeeed

emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1 whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1 whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0

2 years ago

6 x - 2 [ x + 2 ] > 2 - 3 [ x + 3] could u show me step by step on how to do thiz

Dafna11 [192]

Answer:

x > - 3/7

Step-by-step explanation:

6x - 2x - 4 > 2 - 3 (x + 3)

6x - 2x - 4 > 2 - 3x - 9

4x - 4 > 2 - 3x - 9

4x - 4 > - 7 - 3x

4x - 4 + 3x > - 7

7x > - 7 + 4

7x > - 3

8 0

2 years ago

Find two z values, one positive and one negative, that are equidistant from the mean so that the areas in the two tails add to t

levacccp [35]

I think it would be the answer is b.

3 0

3 years ago