So simple... 3\ll=27\100 which equals 27.0 or 0.27
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
First choice:

Explanation:
<em>The probability that the first is a man's card and the second, a woman's card</em> is calculated as the product of both probabilities, taking into account the fact that the second time the number of cards in the hat has changed.
In spite of it is said that the cards are drawn at once, since it is stated a specific order for the cards (first is a man's card and the second, a woman's card) you can model the procedure as if the cards were drawn consecutively, instead of at once.
<u>1. Probability that the first is a man's card</u>
- Number of cards in the hat = 20 (the 20 business card)
- Number of man's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/20 = 1/2.
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<u>2. Probability that the second is a woman's card</u>
- Number of cards in the hat = 19 (there is one less card in the hat)
- Number of wonan's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/19.
<u>3. Probability that the first is a man's card and the second, a woman's card</u>
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That is the first choice.