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Andrew [12]
3 years ago
7

Short Answer Note: Your teacher will grade your responses to the next two questions to ensure you receive proper credit for your

answers. 4. If you wanted to find the difference of what common denominator should you choose? Why? 25 5
PLEASE HELP IF CORRECT I WILL MARK BRAINLIEST ​
Mathematics
2 answers:
Bess [88]3 years ago
8 0

Answer:

5

Step-by-step explanation:

svet-max [94.6K]3 years ago
5 0
Find the multiples of both denominators and find the lowest common factor to determine the best common denominator without needing to simplify later on.
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Which graph represents a quadratic function that has one real zero?
Naddika [18.5K]

Answer:

Step-by-step explanation:

Next time, please share the possible answer choices.

A quadratic function with one real zero actually has TWO real, identical zeros.  The vertex of the graph lies on the x-axis (touching it in only one place).

6 0
4 years ago
Find the coordinates of the missing endpoint if m is the midpoint of AB.
Ne4ueva [31]
E because its not on there
7 0
3 years ago
How do you solve 5÷(4-3)×9-2
4vir4ik [10]
5÷(4-3)×9-2
= 5÷1×9-2
= 5 × 9 - 2
= 43

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3 0
3 years ago
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What system of equations would you use to solve the problem below?
Oduvanchick [21]

Answer: a+c=27,126

Step-by-step explanation:

3 0
2 years ago
One jogger begins his run on a path at a rate of 6 miles per hour. A second jogger starts at the same point of the path as the f
dedylja [7]

Answer:

The answer to your question is: three hours.

Step-by-step explanation:

data

Jogger 1 = 6 mi/h

Jogger 2 = 6.5 miles/h , starts 15 min (0.25 h) after the first Jogger

Time when the second jogger catch the first jogger = ?

Process

Advantage of the first jogger    d = vt = 6(0.25) = 1.5 mi

Distance where they meet       1.5 + 6t = 6.5t

Find the t value                          6.5t - 6t = 1.5

                                                   0.5 t = 1.5

                                                    t = 1.5 / 0.5

                                                    t = 3 hours                                                    

3 0
3 years ago
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