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Greeley [361]
3 years ago
6

PLEASE I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

y = -2x + 5

Step-by-step explanation:

A(4, -3) ;      B(2, 1)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{1-[-3]}{2-4}\\\\= \frac{1+3}{2-4}\\\\= \frac{4}{-2}\\\\= -2

m = -2 ;  A(4,-3)

y - y_{1}=m(x-x_{1})\\\\y -[-3] = (-2)(x - 4)\\\\y + 3 = -2*x -4 *(-2)\\\\y + 3 = -2x + 8\\\\    y = -2x  + 8 - 3 \\\\   y = -2x + 5

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I need help asap please
Zigmanuir [339]
3/5 is smaller then 3/4(you can tell from denominators) 5/8 is smaller then 3/5, and 7/4 is greater then 1, so the only logical one is C. Hope this helped!
8 0
4 years ago
SOLVE each system by graphing PLEASSE
dexar [7]

Answer:


Step-by-step explanation:

The given equations are:

y=-\frac{1}{3}x+3 and y=2x-4

On solving y=-\frac{1}{3}x+3 , we get the graph which is red in colour.

By Putting x=o in the equation⇒y=3

Putting x=-3⇒y=4

Now, plotting the graph for the equation y=2x-4, it is plotted as blue colour by putting x=0⇒y=-4 and by putting x=3⇒y=2, Following the same path, we can plot the two graphs for the given equations.

8 0
3 years ago
I need help on question a and b. please help me asap?!?!?
Stolb23 [73]
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3 0
3 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis
Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

f(x)=6

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

f(x)=-3

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

f(x)=1

Therefore the graph represents a piecewise function, which is defined as

f(x)=\begin{cases}6& \text{ if } x2 \end{cases}

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

lim_{x\rightarrow 2^-}f(x)=6

lim_{x\rightarrow 2^+}f(x)=-3

6\neq-3

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0
3 years ago
Read 2 more answers
I need help please so if you could help that would be nice. Also i will make brainliest
timurjin [86]
No it is not a function. You have to be able to write y=mx+b
5 0
3 years ago
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