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hram777 [196]
3 years ago
6

PLEASE AWNSER THIS SOON I REALLY NEED IT DONE PLUS IT'S DUE SOON!

Mathematics
1 answer:
skad [1K]3 years ago
4 0
(2,1)
(2,-2)
(5,-5)
(-1,-1)
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Alysha’s average speed when walking home from the market was 5 mph, and it takes her 21 minutes longer than when she drives to t
Delicious77 [7]

9514 1404 393

Answer:

  3 minutes

Step-by-step explanation:

Let x represent Alysha's time to drive home from the market.

Speed and time are inversely proportional to each other (for the same distance), so we have ...

  (walking speed)(walking time) = (driving speed)(driving time)

  5(x +21) = (8·5)(x)

  x +21 = 8x . . . . . . . . . divide by 5

  21 = 7x . . . . . . . . subtract x

  3 = x . . . . . . .divide by 7

It takes Alysha 3 minutes to drive home from the market.

3 0
3 years ago
The nearest ten 1202(38)
Misha Larkins [42]
The answer is 120240
4 0
3 years ago
VERY IMPORTANT QUESTION I WILL GIVE 50 POINTS TO WHOEVER ANSWERS THIS QUESTION
solmaris [256]
I think it might be  expression one =14 i think and number 2 is obviously is 19 but you would put parenthesis around 5+4_2+6 

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8 0
3 years ago
The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse
diamong [38]

Answer:  The answer is cosine of that acute angle.


Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

Thus, the ratio is cosine of the acute angle.

7 0
3 years ago
Which of the following inequalities is equivalent<br> to -31 + 12s &lt;3s + 15 ?
Travka [436]

Answer:

 -31+12s

Step-by-step explanation:

3 0
3 years ago
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