8x + 2y = 44
5x + 2y = 35
Since 2y is already common, there is no need for multiplication. Just reverse the signs on the equation.
Like this;
8x + 2y = 44
-5x - 2y = -35
All the additions become subtractions and vice versa.
-2y and +2y get cancelled.
Leaving;
8x = 44
-5x = -35
Now, subtract again.
8x - 5x = 3x
44 - 35 = 9
So;
3x = 9
x = 9 / 3
x = 3
We found 'x' and now we have to find 'y'.
Just substitute.
[8 x 3] + 2y = 44
24 + 2y = 44
2y = 44 - 24
2y = 20
y = 20 / 2
y = 10
Now, we re-check;
[8 x 3] + [2 x 10] = 44
24 + 20 = 44
Explaining the error for #9b is simply doing the whole sum.
Hope this helped! :) I tried my best to explain.
Hey!~
The answer is 25/100.
0/100 (0) and 50/100 (1/2) : The middle is 1/4.
Hope this helps and have a great day!
-Lindsey
The rate of time is measured in feet per minute.
<span>Because distance = rate * time, </span>
<span>Then rate = distance / time, which gives you feet / min. </span>
Answer:
Dimensions of the rectangular plot will be 500 ft by 750 ft.
Step-by-step explanation:
Let the length of the rectangular plot = x ft.
and the width of the plot = y ft.
Cost to fence the length at the cost $3.00 per feet = 3x
Cost to fence the width of the cost $2.00 per feet = 2y
Total cost to fence all sides of rectangular plot = 2(3x + 2y)
2(3x + 2y) = 6,000
3x + 2y = 3,000 ----------(1)
3x + 2y = 3000
2y = 3000 - 3x
y = ![\frac{1}{2}[3000-3x]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B3000-3x%5D)
y = 1500 - 
Now area of the rectangle A = xy square feet
A = x[
]
For maximum area 
A' =
= 0
1500 - 3x = 0
3x = 1500
x = 500 ft
From equation (1),
y = 1500 - 
y = 1500 - 750
y = 750 ft
Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.
two fencing 3(500+500) = $3000
other two fencing 2(750+750) = $3000