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VMariaS [17]
3 years ago
5

POV : ur missing assignments so u looked up an answer and came here check!! ;c

SAT
2 answers:
MissTica3 years ago
4 0
Lol how you doing sweetie
kifflom [539]3 years ago
3 0
Lol same bro how’s ur day
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Answer:

A. 2 hours walking; 12 hours running.

I am aware this is a multiple choice question. There is only one answer.

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The smiths took out a $130,000, 30-year mortgage at an apr of 6.5%. the monthly payment was $821.69. what will be their total in
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The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
AlladinOne [14]

Recall that √x has a domain of x ≥ 0.

So, f(x) is defined as long as

(x + 1)/(x - 1) ≥ 0

• We have equality when x = -1

• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:

\begin{cases}x+1>0 \implies x>-1 \\ x-1>0 \implies x>1\end{cases} \implies x > 1

\begin{cases}x+1

Then the domain of f(x) is

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On the other hand, g(x) is defined by two individual square root expressions with respective domains of

• x + 1 ≥ 0   ⇒   x ≥ -1

• x - 1 ≥ 0   ⇒   x ≥ 1

but note that g(1) is undefined, so we omit it from the second domain.

Then g(x) is defined so long as both x ≥ -1 *and* x > 1 are satisfied, which means its domain is

x > 1

f(x) and g(x) have different domains, so they are not the same function.

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