Answer:
97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].
Step-by-step explanation:
We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;
32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. =
~ 
where,
= sample average number of miles =
= 30.25
s = sample standard deviation =
= 4.71
n = sample of tires = 12
= population average number of miles
<em>Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>
<u>So, 97% confidence interval for the population mean, </u>
<u> is ;</u>
P(-2.55 <
< 2.55) = 0.97 {As the critical value of t at 11 degrees of
freedom are -2.55 & 2.55 with P = 1.5%}
P(-2.55 <
< 2.55) = 0.97
P(
<
<
) = 0.97
P(
<
<
) = 0.97
<u>97% confidence interval for</u>
= [
,
]
= [
,
]
= [26.78 miles, 33.72 miles]
Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].