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3 years ago

80 is what percent of 1600

Mathematics

2 answers:

34kurt3 years ago

7 0

80 is 5% of 1600. Hope this helps :)

Effectus [21]3 years ago

7 0

The answer to this question is:
5% or 0.05
You get the answer by dividing 80/1600=0.05 or move the decimal over two spaces and get your percentage.

I hope this helps!!!!!!!!!

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How to simplify -(-7y+12)

faust18 [17]

-(-7y + 12) = 7y - 12
u are distributing the -sign through the parenthesis...so u take the number outside of the parenthesis (and if it just a sign, the number is 1)...and u multiply it by everything in the parenthesis.
-1(-7y + 12) = -1 * -7y + (-1) * 12 = 7y + (-12) = 7y - 12

7 0

3 years ago

What is 4 over 2 as a fraction

Nesterboy [21]

To write 4 over 2: 4/2

8 0

3 years ago

Read 2 more answers

How do I solve <br><img src="https://tex.z-dn.net/?f=%20%20%5Csin%28%20a%20%29%20%20%3D%20.8325" id="TexFormula1" title=" \sin(

Serga [27]

Answer:

$a=56.4\degree$

Step-by-step explanation:

Let $a$ be an acute angle.

To solve: $\sin(a)=0.8325$ , we take the sine inverse of both sides to obtain:

$\sin^{-1}(\sin(a))=\sin^{-1}(0.8325)$

Recall composition property of a function and its inverse function.

$f^{-1}(f(x))=x$

We apply this property to the left hand side to obtain;

$a=\sin^{-1}(0.8325)$

We now use our scientific calculator to obtain;

$a=56.3564115\degree$

We round to the nearest tenth to obtain;

$a=56.4\degree$

4 0

3 years ago

Regular Hourly Rate = $6.50 Total Work Hours = 48 Overtime Rate = Time

Vikki [24]

Answer:

2212$

Step-by-step explanation:

6 0

3 years ago

Prove that C(50,3) + C(50,4) = C(51,4)

valkas [14]

By definition of the binomial coefficient,

$C(n,k) = \dfrac{n!}{k!(n-k)!}$

so we have

$C(50,3) + C(50,4) = \dfrac{50!}{3!47!} + \dfrac{50!}{4!46!} \\\\ = \dfrac{50!}{3!46!} \left(\dfrac1{47} + \dfrac14\right) \\\\ = \dfrac{50!}{3!46!} \times \dfrac{51}{188} \\\\ = \dfrac{51!}{3!46!} \times \dfrac1{4\times47} \\\\ = \dfrac{51!}{4!47!} \\\\ = \dfrac{51!}{4!(51-4)!} = C(51,4)$

as required.

5 0

2 years ago