Question

Determine whether the function represented by each equation is quadratic. F(x)=0.01-0.2x+x^2

Answer 1

Answer: x=0.1

Step-by-step explanation:

Given

The function is given by $F(x)=x^2-0.2x+0.01$

A standard quadratic equation is given by $ax^2+bx+c=0$

The given equation has an exponent of x as 2 which confirms it is a quadratic equation. Compare it with the standard equation

$a=1,b=0.2,c=0.01$

Therefore, the given equation is the quadratic equation.

Its solution is given by

$\Rightarrow x=\dfrac{0.2\pm \sqrt{(-0.2)^2-4\times 1\times 0.01}}{2\times 1}\\\\\Rightarrow x=0.1$