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ValentinkaMS [17]
3 years ago
5

What is the slope of the line through the points (0,-3) and (2,1)?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer:

alright so you got 2 points! now this is the slope formula! y2-y1/x2-x1

okay let's label your points! (x1 0,y1 -3) (x2 2,y2 1)

let's follow the formula this makes it so we can solve! 1--3/2-0

I understand you may get a decimal but don't use 2.5 use a fraction because teachers seem to like fractions and general decimals can be hard to use (experience lol) 2.5 is 5/2 so this means your slope is 5/2

this formula works every single time and if you memorize it you can do any other problems with 2 points! please memorize y2-y1/x2-x1

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Hi there!

\large\boxed{ 14.875}

Our interval is from 0 to 3, with 6 intervals. Thus:

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(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =

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We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

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As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}

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