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Natasha_Volkova [10]
3 years ago
13

Identify square root of 3 as either rational or irrational, and approximate to the tenths place.

Mathematics
2 answers:
finlep [7]3 years ago
6 0
Sadly I didn’t even know that
dmitriy555 [2]3 years ago
3 0

Answer:

It is an irrational number, \sqrt{3} as a decimal rounded to the tenth place is 1.7

Step-by-step explanation:

All square roots are irrational numbers

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siniylev [52]
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The graph goes through (0,0), thereforea(0 - 10)² + 15 = 0100a = -15a = -0.15
The equation is y = f(x) = -0.15(x - 10)² + 15
The graph is shown below.
Part A
Note that y = f(x).
The x-intercepts identify values where the function or  y=0. The x-intercepts occur at x=0 and x=20, or at (0,0) and (20,0).
The maximum value of y occurs at the vertex (10, 15) because the curve is down due to the negative leading coefficient of -0.15.
The curve increases in the interval x = (-∞, 10) and it decreases in the interval x = (10, ∞).
Part B
When x=12, y = -0.15(12 - 10)² + 15 = 14.4When x=15, y = -0.15(15 - 10)² + 15 = 11.25
The average rate of change between x =12 to x = 15 is(11.25 - 14.4)/(15 - 12) = -1.05
This rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases in the interval x =[12, 15].
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1/2 pounds,


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2 years ago
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Answer:

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Answer:

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Step-by-step explanation:


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