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vekshin1
3 years ago
6

Question 2/5

Mathematics
1 answer:
ozzi3 years ago
4 0

i think the answer is 122,400

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Principal = 5300=5300 rupees
PSYCHO15rus [73]

Answer:

Using the formula:

A=P+I

where

A is the total amount

P is the principal

I is the Simple Interest

As per the statement:

Principal(P) = 5300 rupees.

rate of interest(r) = 6.5% = 0.065

Total amount(A) = 6678 rupees.

Then using above formula we have;

6678 = 5300+I

Subtract 5300 both sides we get;

1378 = I

or

I = \$1378

We have to find the time period.

Using formula of Simple interest:

I = Prt

where r is the rate of interest (in decimal)

here, r = 6.5% = 0.065

Substitute the given values top find t:

1378 = 5300 \cdot 0.065 \cdot t

⇒1378 = 344.5t

Divide both sides by 344.5 we have;

4  = t

Therefore, the time period t in years is 4 years

8 0
4 years ago
Goodd Luck!<br> llllllllllaa
Setler79 [48]
The positive integers are: +2, +11, +8, 28, and 13
the negative integers are: -7, -9, -11, and -3
the 0 should go in the circle between the two charts
3 0
3 years ago
Read 2 more answers
Use the graph to answer the questions.
Contact [7]
1. The domain of the sequence shown is {1, 2, 3, 4, 5}. This is best matched by the description Natural numbers.

2. The common ratio is 3/1 = 9/3 = 3.

3. The first term of this geometric sequence is 1. The common ratio is 3. So, the explicit formula is f(x) = 1(3)^(x-1)
10 0
4 years ago
Read 2 more answers
You need to construct an open-top rectangular box with a square base that must hold a volume of exactly 475 cm3. The material fo
zepelin [54]

Answer:

The dimensions of the box are:

x =  8,93 cm       and     h  =   5,95 cm

C(min) =  850,69 cents

Step-by-step explanation:

The volume of the box is:

V = x²*h          where    x is the side of the square base  and h the height

then    h  =  V/ x²  ⇒    h = 475 / x²

The total cost of box C is:

C  = C₁  +  4*C₂      Where C₁  and C₂  are the costs of the base and one lateral side respectevily

Then cost C =  8*x²   + 4* 6*h*x

The cost C as a function of x is

C(x)  =  8*x²  + (24* 475 /x² )*x

C(x)  =  8*x²  +  11400/x

Tacking derivatives on both sides of the equation

C´(x)  =  16*x -  11400/x²

C´(x)  =  0     ⇒    16*x  -  11400/x²  = 0

16*x³  =  11400     ⇒   x³  =  11400/16

x³ =  712,5

x  =  8,93  cm

and    h   =  475 / (8,93)²      ⇒      h  =  5,95  cm

C(min)  =  8*79,77  +  4* ( 8,93)*5,95

C(min)  =  638,16  +  212,53

C(min)  =  850,69 cents

To check if value x = 8,93 would make C(x) minimum we go to the second derivatives

C´´(x) =  16  +  22800/x³ > 0

Then we have a minimum of C at  x = 8,93

4 0
4 years ago
Tina says that 3.4 x 105 is greater than 8.25 x 104. Is she correct? Justify your answer.
Anna71 [15]

Answer:

No, Tina is not correct since 3.4 × 105 = 357 and 8.25 × 104 = 858

6 0
3 years ago
Read 2 more answers
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