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salantis [7]
2 years ago
6

Tina says that 3.4 x 105 is greater than 8.25 x 104. Is she correct? Justify your answer.

Mathematics
2 answers:
Anna71 [15]2 years ago
6 0

Answer:

No, Tina is not correct since 3.4 × 105 = 357 and 8.25 × 104 = 858

Umnica [9.8K]2 years ago
4 0
No that is not correct 3.4x105=425 and 8.25x104=858
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7 times the number of cookies in the jar plus 5 more from the tray is 54. How many cookies are in the jar?
Digiron [165]

Answer:

The number of cookies in the jar is 7.

If we include the 5 cookies from the tray in the jar the total number of cookies would be 5 + 7 = 12

Step-by-step explanation:

<em>Consider the number of cookies in the jar as 'x'. Hence the equation formed would be:-</em>

7(x) + 5 = 54

7x + 5 = 54

7x = 54 - 5

7x = 49

x = \frac{49}{7}

x = 7

The number of cookies in the jar is 7.

If we include the 5 cookies from the tray in the jar the total number of cookies would be 5 + 7 = 12

<em>Hope this helps.</em>

8 0
2 years ago
Find the value of two numbers if their sum is 12 and their difference is 4.
AlladinOne [14]

Answer:

8 and 4

Step-by-step explanation:

8 0
3 years ago
Please help, much needed. A lot of points
svetoff [14.1K]

Answer:

A. -9

Step-by-step explanation:

If one of the variables were negative than, it would not be able to equal 2/7.

8 0
2 years ago
Read 2 more answers
It says factor 49x-28
kvasek [131]

Answer:

7(7x-4)

Step-by-step explanation:

We can factor a 7 from each term

49x = 7*7x

28 = 7*4

49x -28

7(7x-4)

6 0
3 years ago
Read 2 more answers
University officials say that at least 70% of the voting student population supports a fee increase. If the 95% confidence inter
yanalaym [24]

Answer:

We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.

Step-by-step explanation:

The interpretation of a  x% confidence interval of proportions being between a and b is that:

We are x% sure that the true proportion of the population is between a and b.

If the 95% confidence interval estimating the proportion of students supporting the fee increase is (0.75; 0.85), what conclusion can be drawn

We are 95% sure that the true proportion of students that supports a fee increase is between 0.75 and 0.85.

3 0
3 years ago
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