A school assembly had 75 students in attendance, and 40% of them were first-graders. How many first-graders were at the assembly
2 answers:
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Answer:
Problem:
Consider a rectangle such that the width of the rectangle is 12 more than thrice its length. Find a formula for the width in terms of its length. Take length as 'x'.
Step-by-step explanation:
Consider a rectangle such that the width of the rectangle is 12 more than thrice its length. Find a formula for the width in terms of its length.
Let the length be 'x'.
Therefore, as per question, width is 12 more than thrice the length.
Thrice the length means . 12 more means adding 12 to the result.
Therefore, the width of the rectangle is .
So, the above question expresses the width of the rectangle as which is the required answer.
Answer:
5 and 7.
Step-by-step explanation:
Hey! So to start you need to create an algebraic expression. You can express this problem through the following equation:
*Note: if x is an odd integer, x + 2 is the next consecutive odd integer.
Expanding, you get:
And moving the 35 to the other side, you get a simple quadratic.
Solving by factoring:
This means two possible solutions for the smaller consecutive number are -7 and 5. However the question asks for two positive odd integers, so one of the numbers must be 5. The next will be 7(as its x + 2).