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3 years ago

Can someone please solve this problem for me?

Mathematics

1 answer:

statuscvo [17]3 years ago

5 0

Answer:

5 and 7.

Step-by-step explanation:

Hey! So to start you need to create an algebraic expression. You can express this problem through the following equation:

*Note: if x is an odd integer, x + 2 is the next consecutive odd integer.

$x *(x+2)=35$

Expanding, you get:

$x^{2}+2x = 35.$

And moving the 35 to the other side, you get a simple quadratic.

$x^{2}+2x -35 =0.$

Solving by factoring:

$(x+7)(x-5)$

This means two possible solutions for the smaller consecutive number are -7 and 5. However the question asks for two positive odd integers, so one of the numbers must be 5. The next will be 7(as its x + 2).

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Part 2: Identify the vertex, focus, and directrix of each. Then sketch the graph.

Andre45 [30]

Answer: $\bold{1.\quad \text{Vertex}}:(-3,-6)\qquad \text{Focus}:\bigg(-3,-\dfrac{17}{4}\bigg)\qquad \text{Directrix}:y=-\dfrac{19}{4}$

2. Vertex: (-5, 4) Focus: (-6, 4) Directrix: x = -4

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k or x = a(y - k)² + h

(h, k) is the vertex
p is the distance from the vertex to the focus
-p is the distance from the vertex to the directrix

$\bullet \quad a=\dfrac{1}{4p}$

1) y = (x + 3)² - 6 → a = 1 (h, k) = (-3, -6)

$a=\dfrac{1}{4p}\qquad \rightarrow \qquad 1=\dfrac{1}{4p} \qquad \rightarrow \qquad p=\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad =\dfrac{-18}{4}+\dfrac{1}{4}\\\\.\qquad = -\dfrac{17}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(-3,-\dfrac{17}{4}\bigg)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=\dfrac{-18}{4}-\dfrac{1}{4}\\\\.\qquad \quad y= -\dfrac{19}{4}$

****************************************************************************************

$2.\quad x=-\dfrac{1}{4}(y-4)^2-5\qquad \rightarrow \quad a=\dfrac{1}{4}\qquad (h, k)=(-5,4)$

$a=\dfrac{1}{4p}\qquad \rightarrow \qquad -\dfrac{1}{4}=\dfrac{1}{4p} \qquad \rightarrow \qquad p=-1\\\\\text{Focus = Vertex + p}\\\\.\qquad =-5+\ -1\\\\.\qquad = -6\qquad \rightarrow \qquad \text{Focus}=(-6,4)\\\\\\\text{Directrix: y = Vertex - p}\\\\.\qquad \quad y=-5+\ -1\\\\.\qquad \quad y= -4$

7 0

4 years ago

Solve the proportions using cross products. Round to the nearest hundredth is necessary. 21miles/49hours = 15miles h hours

SSSSS [86.1K]

$\dfrac{21}{49}=\dfrac{21:7}{49:7}=\dfrac{3}{7}\\\\\dfrac{21}{49}=\dfrac{15}{h}\to\dfrac{3}{7}=\dfrac{15}{h}\qquad\text{cross multiply}\\\\3h=(7)(15)\\\\3h=105\qquad\text{divide both sides by 3}\\\\\boxed{h=35}\\\\Answer:\ 35\ hours$

8 0

4 years ago

The polynomial x^2-(k+1)x-3 has a factor (x-k+1). find k

astra-53 [7]

Answer:

Step-by-step explanation:

please help some one I also need help on this

6 0

3 years ago

Review the steps of the proof of the identity

koban [17]

Answer:

step 2

and then also in step 3 compensating the error in step 2

Step-by-step explanation:

I think I just answered this for another post.

sin(a - b) = sin(a)cos(b) - cos(a)sin(b)

so, step 1 is correct :

sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2)

but step 2 suddenly and incorrectly switched that central "-" to a "+".

yes, sin(3pi/2) = -1, but that is still an explicit factor in step 2. so it was not used to flip the central operation from subtraction to addition, and therefore this change was a mistake.

then, in step 3, another error was made by just ignoring the "-" sign of "-1" and still keeping the central "+" operation. this error compensated for the error in step 2 bringing us back by pure chance to the right result.

5 0

2 years ago

PLS HELP I WILL GIVE BRAINLY IF YOUR RIGHT Which expression is equivalent to 4x^2+(5x−7x^2)−4−(3x+5)?

larisa86 [58]

Answer:

The answer is -3x²+2x-9.

6 0

3 years ago