Answer:
Horizontal asymptote of the graph of the function f(x) = 25/1+4x is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0. There is also a <em>vertical</em> asymptote at x=-1/4
When denominator's degree (1) is higher than nominator's degree (0) then the horizontal asymptote is y=0
Answer:
86/5 or 17.2
Step-by-step explanation:
5 + 21/5 + 8
46/5 + 8
86/5 or 17.2
Looks like the integral is supposed to read

The same integral in the required order is

Answer:
substitute the unknown with the values given ie
3(3) - 4 (2)
you get 9-8
= 1