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stich3 [128]
3 years ago
15

Enter the trigonometric equation you would use to solve for x in the following right triangle. Do not solve the equation

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

tan^{-1}(\frac{7}{24} )

Step-by-step explanation:

In the given triangle length of the legs have been given as 7 and 24 units

We have to form the equation to solve for x.

We will apply tan in the given triangle

tanx = \frac{\text{opposite leg}}{\text{adjacent leg}}

tanx = \frac{7}{24}

So x = tan^{-1}(\frac{7}{24} )

Therefore, x =  tan^{-1}(\frac{7}{24} )

Iteru [2.4K]3 years ago
6 0
Angle x = arc tangent (7 / 24)
Angle x = arc tangent ( <span> <span> <span> 0.291666666...) </span> </span> </span>





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The answer is 9. because... (8+9) + 32= 49
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Identify the data set that could be quadratic. HELP ASAP!!
Ne4ueva [31]

Answer:

Option B can be quadratic.

Step-by-step explanation:

Take a look at the data.

A quadratic equation is of the form ,

y = ax^{2} +bx + c,

where, a,b,c are constants.

<em>To find an unknown equation of 3 variables,</em>

<em>we need 3 points lying on the equation.</em>

here they have given, 5 points, meaning all should lie on the curve.

<em>For first option,</em> inserting first 3 points to find equation, we get equation as,

y = x^{2} -4x +11, but the rest points don't satisfy the curve.

So first option is not quadratic.

Similarly, it can be shown that option C and D are also not quadratic.

While, in option B, it is clear that for every y, x is y squared,

x = y^{2}, thus quadratic in nature.

6 0
3 years ago
Simplify (8x^3-5x-1)-(7x^2+6x-10)
irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

use the communative property to reorder the equation

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3 years ago
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Gnoma [55]

4Th option is correct ✔️ ✔️

5 0
3 years ago
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kobusy [5.1K]

The equation of the line is y - 3 = 5(x - 8) ⇒ c

Step-by-step explanation:

The point-slope form of the linear equation is y-y_{1}=m(x-x_{1}) , where:

  • m is the slope of the line
  • (x_{1},y_{1}) is a point on the line

∵ The line passes through point (8 , 3)

∴ x_{1} = 8 and y_{1} = 3

∵ The slope of the line is 5

∴ m = 5

- Substitute these values in the form of the equation below

∵ y-y_{1}=m(x-x_{1})

∴ y - 3 = 5(x - 8)

The equation of the line is y - 3 = 5(x - 8)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

3 0
3 years ago
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