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3 years ago

Find the value of y and (4x+8)°

Mathematics

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

Algebra For what values of the variables must ABCD be a parallelogram?

23. A 2y + 2 B 24. B

(3x + 10)

(8x + 5)º

3x + 6

54°

Зу - 9 с

ly+4

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Which equation could be used to solve for the length of side c, given a = 5, b = 12, and C = 72°?

dolphi86 [110]

Answer:

law of cosines

c^2=(5)^2+(12)^2-2(5)(12)cos72

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Convert r = 8cos θ to rectangular form.

nikklg [1K]

Answer:

$(x-4)^2+y^2=16$

This is a circle with radius $\sqrt{16}=4$ and center $(4,0)$ .

Step-by-step explanation:

Recall the following:

$x=r\cos(\theta)$

$y=r\sin(\theta)$

$\frac{y}{x}=\tan(\theta)$

$x^2+y^2=r^2$

We are given $r=8\cos(theta)$ .

Multiply both sides by $r$ :

$r(r)=8\cos(\theta)r$

Reorder on right and simplify on left:

$r^2=8r\cos(theta)$

We can now make some replacements from our "Recall" section:

$x^2+y^2=8x$

We can probably leave like this, but sometimes we are required to put in a more identifying form.

This is a circle. I'm going to write in the form $(x-h)^2+(y-k)^2=r^2$ .

Subtract $8x$ on both sides:

$x^2-8x+y^2=0$

$x^2-8x+\text{(blank)}+y^2=0+\text{(blank)}$

We are going to fill those "blanks" in so that we can complete the square for the $x$ part.

$x^2-8x+(\frac{-8}{2})^2+y^2=0+(\frac{-8}{2})^2$

$(x+\frac{-8}{2})^2+y^2=0+(-4)^2$

$(x-4)^2+y^2=0+16$

$(x-4)^2+y^2=16$

So our equation is that of a circle with radius $\sqrt{16}=4$ and center $(4,0)$ .

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3 years ago

Order the decimal numbers below from the smallest on the left to largest on the right

Ahat [919]

Answer:

0.0837 , 0.088 , 0.8 , 0.84

Step-by-step explanation:

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3 years ago

who walks at a faster rate : somone who walks 60 feet in 10 seconds or someone who walks 42 feet in 6 seconds

fenix001 [56]

60/10=6f/s

42/6=7f/s

7>6, so the person who walks 42 feet in 6 seconds is faster. :)

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2 years ago

Find the value of y and (4x+8)°​

Find the value of y and (4x+8)°