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Tatiana [17]
3 years ago
8

Ally collects stickers as a hobby. She gives her sisters of her stickers.

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

\frac{16}{25}

Step-by-step explanation:

Ally gives her sister = 1/5 stickers

Ally gives her cousin = 1/5 of the remainder stickers

Assume Number of sticker Ali has = 1

Remainder after giving stickers to her sister = 1 - 1/5 = 4/5

Number of stickers she gave her sister = \frac{1}{5}\times\frac{4}{5}

         =\frac{4}{25}

Sticker she has = 1-\frac{1}{5}-\frac{4}{25}

=\frac{25-5-4}{25}

=\frac{16}{25}

Sticker left with Ally is equal to \frac{16}{25}.

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(180-14):2+14= 166:2+14= 83+14= 97° (bigger angle)
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Find the side length of a cube with a volume of 166 m
marin [14]
The answer is 5.5 m.


Cube
Volume = length x width x height

Since the length, width and the height are the same in cube, the formula can be:

Volume = length^3


Let x metres be the side length of the cube.

166 = x^3

x = ∛166

x = 5.495864.....

x = 5.5 (nearest tenth)
8 0
3 years ago
Ralph is 3 times as old as Sara. In 4 years, Ralph will be only twice as old as Sara will be then. Find Ralph's age now. Ralph's
IgorLugansk [536]
Let
R = Ralph's age
S = Sara's age

First statement is translated as:
S = 3R

Second statement is translated as:
S + 4 = 2(R + 4)

Use the first equation to be substituted into the second one in terms of R which is the one we are actually going to solve for Ralph's age.
Since S = 3R, then
3R + 4 = 2(R + 4)
3R + 4 = 2R + 8
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7 0
3 years ago
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on monday sheila sold 20 apples, on tuesday she sold 12 apples, on wednesday she sold 20 apples, and on thursday she sold 28 app
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The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?
pashok25 [27]

Answer:

Yes, it is true that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1.

Step-by-step explanation:

Let us try to factorize x^4+3x^3-2x^2-3x+1

x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3

Let us try to make a whole square of the given terms:

\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\

--------------

Formula used above:

a^{2} -2 \times a \times b +b^{2}  = (a-b)^2

In the above equation, we had a = x, b = 1.

--------------

Further solving the above equation, taking 3x common out of 3x^3-3x

\Rightarrow (x^2-1)^2+3x(x^2-1)\\

Taking (x^{2} -1) common out of the above term:

\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)

So, the two factors are (x^2-1)\ and\ (x^2+3x-1).

\therefore The statement that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1 is <em>True.</em>

7 0
3 years ago
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