Differentiating both sides of
![x^3-y^3=1](https://tex.z-dn.net/?f=x%5E3-y%5E3%3D1)
with respect to <em>x</em> yields (using the chain rule)
![3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0](https://tex.z-dn.net/?f=3x%5E2%20-%203y%5E2%20%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%20%3D%200)
Solve for d<em>y</em>/d<em>x</em> :
![3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 3y^2\dfrac{\mathrm dy}{\mathrm dx} = 3x^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{3x^2}{3y^2} = \dfrac{x^2}{y^2}](https://tex.z-dn.net/?f=3x%5E2%20-%203y%5E2%20%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%20%3D%200%20%5C%5C%5C%5C%203y%5E2%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%20%3D%203x%5E2%20%5C%5C%5C%5C%20%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%20%3D%20%5Cdfrac%7B3x%5E2%7D%7B3y%5E2%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7By%5E2%7D)
The answer is then D.
Answer:
perimeter = 45 in.
area = 123.5 in.^2
Step-by-step explanation:
I assume this is a rectangle.
L = 13 in.
W = 9.5 in.
perimeter = 2(L + W) = 2(13 in. + 9.5 in.) = 2(22.5 in.) = 45 in.
area = LW = 13 in. * 9.5 in. = 123.5 in.^2
72, 96, 84, 12
72 + (7x+24) = 180
7x + 96 = 180
7x = 84
x = 12
66.6% because 100 is 2/3rds of 150
X^2-8x-20 and if you rewrite that it’s (x-10) (x+2)