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frosja888 [35]
3 years ago
8

A triangle has side lengths of n, n – 3, and 2(n − 2). If the perimeter of the triangle is at least 37 units, what is the value

of n?
OA.

n> 11

OB

n> 8

O C.

n > 10.5

OD

n > 7.5
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

n = 11

Step-by-step explanation:

The side length of a triangle are n,n-3 and 2(n-2).

The perimeter of the triangle, P = 37 units

We need to find the value of n.

Perimeter = sum of all sides

n+n-3 +2(n-2) = 37

2n-3+2n-4 = 37

4n -7 = 37

4n = 37+7

4n = 44

n = 11

So, the value of n is 11.

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