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frosja888 [35]
3 years ago
8

A triangle has side lengths of n, n – 3, and 2(n − 2). If the perimeter of the triangle is at least 37 units, what is the value

of n?
OA.

n> 11

OB

n> 8

O C.

n > 10.5

OD

n > 7.5
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

n = 11

Step-by-step explanation:

The side length of a triangle are n,n-3 and 2(n-2).

The perimeter of the triangle, P = 37 units

We need to find the value of n.

Perimeter = sum of all sides

n+n-3 +2(n-2) = 37

2n-3+2n-4 = 37

4n -7 = 37

4n = 37+7

4n = 44

n = 11

So, the value of n is 11.

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The circumference of a circle is 30t. What is its area? ​
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Answer:

A=\frac{225t^2}{\pi} given the circumference is 30t.

Step-by-step explanation:

The circumference of a circle is C=2\pi r and the area of a circle is A=\pi r^2 assuming the radius is r for the circle in question.

We are given the circumference of our circle is 2 \pi r=30t.

If we solve this for r we get: r=\frac{30t}{2\pi}.  To get this I just divided both sides by 2\pi since this was the thing being multiplied to r.

So now the area is A=\pi r^2=\pi (\frac{30t}{2 \pi})^2.

Simplifying this:

A=\pi (\frac{30t}{2 \pi})^2.

30/2=15 so:

A=\pi (\frac{15t}{\pi})^2.

Squaring the numerator and the denominator:

A=\pi (\frac{(15t)^2}{(\pi)^2}

Using law of exponents or seeing that a factor of \pi cancels:

A=\frac{(15t)^2}{\pi}

A=\frac{15^2t^2}{\pi}

A=\frac{225t^2}{\pi}

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3 years ago
I don't understand how to do it
leonid [27]
I don't know what question you are but basically to find the the area of something u would either add and then multiply or just multiply . It depends on how your teacher taught you
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