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Marrrta [24]
3 years ago
8

Find the value of x to the nearest tenth​

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0

Answer:

9.0

Step-by-step explanation:

x = 7 / cos 39°

= 7 / 0.7771

= 9.0

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Infinito álgebra For -2x-9y=-25 and -4x-9y=-23
Levart [38]
-2x -9y = -25
-(-4x -9y =-23)
2x = -2
x = -1

-2(-1) -9y = -25
2 - 9y = -25
-9y = -25 -2
-9y = -27
y = 3
(-1,3)
7 0
3 years ago
The distribution of the average amount of sleep per night gotten by college students is roughly bell-shaped with mean 412 minute
kirza4 [7]

Answer:

P(X

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(412,68)  

Where \mu=412 and \sigma=68

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel and we got:

P(z

4 0
3 years ago
Please help me thank you so much have a great day and also be nice to others and especially yourself
ioda
8 inches because 80/10=8
6 0
2 years ago
Read 2 more answers
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
What is the slope of this line?<br><br> A. 1/3<br> B. 1/2<br> C. 1<br> D. 2
HACTEHA [7]

Slope = rise / run

so answer is

C. 1

6 0
3 years ago
Read 2 more answers
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