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3 years ago

write the six digit number that has the digit 4 in the thousands’ place, with each of the remaining digits being 3.

Mathematics

1 answer:

Rus_ich [418]3 years ago

6 0

I’m pretty sure that the answer is 334333

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Anika [276]

using pythagorean theorem

a^2 + b^2 =c^2

a^2 +8^2 =14^2

a^2 +64 = 196

subtract 64 from each side

a^2 = 132

take the square root of each side

a^2 = sqrt (132)

a=11.48912529

a =11.5

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3 years ago

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ra1l [238]

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Inga [223]

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8 0

3 years ago

Find each product or quotient.

solniwko [45]

-38(-3) = 114

-72/(-12) = 6

-9 x 23 = -207

-150/5 = -30

564 / -4 = -141

<h3>Solution:</h3>

Given that, we have to find each product or quotient

-38(-3)

It is a product, so we have to find product value

$-38(-3)=38 \times 3=114$

-72 / (-12)

It is division, so we have to find the quotient

$\frac{-72}{-12}=\frac{72}{12}=6$

-9 x 23

It is a product, so we have to find product value

$-9 \times 23=-207$

- 150 / 5

It is division, so we have to find quotient

$\frac{-150}{5}=-30$

564 / -4

It is division, so we have to find the quotient

$\frac{564}{-4}=-141$

3 0

4 years ago

What is the simplified form of 3 over 4x plus 3 + 21 over 8 x squared plus 26x plus 15

arsen [322]

This is the concept of algebra, we are required to add up the terms given above, here we shall have:
3/(4x)+21/(8x)+26x+15
when we sum up we get:
27/(8x)+26x+15
=(27+208x^2+120x)/(8x)
The simplified form of the summation of the terms is:
(27+208x^2+120x)/(8x)

4 0

3 years ago