Question

If the dimensions of the following cylinder are doubled, what factor will the surface area change by?

Answer 1

Answer:

4

Step-by-step explanation:

Answer 2

To solve this problem you must apply the proccedure shown below:
 1. You have that the radius and the height of the cylinder are:
 $r=8 in \\ h=6 in$
 2. So, you must calculate the area:
 $A1=2 \pi (r+h)$
 3. Substitute the values into the formula:
 $A1=2 \pi (8 in)(8 in+6in) \\ A1=703.71 in^{2}$
 4. When the radius and the height are doubled, you obtain:
 $A2=2 \pi (16 in)(16 in+12 in) \\ A2=2814.86 in^{2}$
 5. The factor is:
 $F=2814.8 in^{2}/703.71 in^{2} \\ F=4$
 The answer is: B. $4$