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mezya [45]
3 years ago
13

If the dimensions of the following cylinder are doubled, what factor will the surface area change by?

Mathematics
2 answers:
Hatshy [7]3 years ago
5 0

Answer:

4

Step-by-step explanation:

AVprozaik [17]3 years ago
4 0
To solve this problem you must apply the proccedure shown below:
 1. You have that the radius and the height of the cylinder are:
 r=8 in \\ h=6 in
 2. So, you must calculate the area:
 A1=2 \pi (r+h)
 3. Substitute the values into the formula:
 A1=2 \pi (8 in)(8 in+6in) \\ A1=703.71  in^{2}
 4. When the radius and the height are doubled, you obtain:
 A2=2 \pi (16 in)(16 in+12 in) \\ A2=2814.86 in^{2}
 5. The factor is:
 F=2814.8 in^{2}/703.71  in^{2}  \\ F=4
 The answer is: B. 4

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A cylindrical can contains an unknown number of golf balls. The can has a height of 10 inches and a volume of 15.625 Pi inches c
AlladinOne [14]

20 golf balls can fit in the can.

<u>Step-by-step explanation:</u>

Given:

Height (h) = 10 Inches

Volume of 15.625 Pi inches cube.

To Find:

How many balls can be filled in that can.

Solution:

Diameter of the golf ball [as per standard value] = 1.68 in

Radius of the golf ball = \frac{1.68}{2}  = 0.84 in

Volume of the golf ball = \frac{4\pi r^3}{3}

                                      = \frac{4\pi (0.84)^3}{3}

                                       = 2.5  (or)   0.79 \pi inches

Volume of the can = 15.625\pi  in^3

Now we have to divide the volume of the can by the volume of the golf ball, we will get =  \frac{15.625 \pi }{0.79\pi } = 19.7 balls

Thus we can conclude that approximately 20 balls can be filled in that can.

7 0
4 years ago
PLEASE HELP!!! the image is below WILL MARK BRAINLEIST!!!
Sonja [21]

Answer:

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6 0
3 years ago
What is the simplified form? (4/7)^3<br> a. 343/64<br> b. 21,952<br> c. 407<br> d. 64/343
charle [14.2K]


=(4/7)^3

=(4/7)*(4/7)*(4/7)

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Answer is D.

8 0
3 years ago
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Answer:

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saveliy_v [14]
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