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ivanzaharov [21]
3 years ago
5

A cylindrical can contains an unknown number of golf balls. The can has a height of 10 inches and a volume of 15.625 Pi inches c

ubed. How may golf balls fill the can if they are uniform in size to the container?
Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

20 golf balls can fit in the can.

<u>Step-by-step explanation:</u>

Given:

Height (h) = 10 Inches

Volume of 15.625 Pi inches cube.

To Find:

How many balls can be filled in that can.

Solution:

Diameter of the golf ball [as per standard value] = 1.68 in

Radius of the golf ball = \frac{1.68}{2}  = 0.84 in

Volume of the golf ball = \frac{4\pi r^3}{3}

                                      = \frac{4\pi (0.84)^3}{3}

                                       = 2.5  (or)   0.79 \pi inches

Volume of the can = 15.625\pi  in^3

Now we have to divide the volume of the can by the volume of the golf ball, we will get =  \frac{15.625 \pi }{0.79\pi } = 19.7 balls

Thus we can conclude that approximately 20 balls can be filled in that can.

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