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ivanzaharov [21]

4 years ago

5

A cylindrical can contains an unknown number of golf balls. The can has a height of 10 inches and a volume of 15.625 Pi inches c

ubed. How may golf balls fill the can if they are uniform in size to the container?

1 answer:

AlladinOne [14]4 years ago

7 0

20 golf balls can fit in the can.

<u>Step-by-step explanation:</u>

Given:

Height (h) = 10 Inches

Volume of 15.625 Pi inches cube.

To Find:

How many balls can be filled in that can.

Solution:

Diameter of the golf ball [as per standard value] = 1.68 in

Radius of the golf ball = $\frac{1.68}{2} = 0.84 in$

Volume of the golf ball = $\frac{4\pi r^3}{3}$

= $\frac{4\pi (0.84)^3}{3}$

= $2.5 (or) 0.79 \pi inches$

Volume of the can = $15.625\pi in^3$

Now we have to divide the volume of the can by the volume of the golf ball, we will get = $\frac{15.625 \pi }{0.79\pi } = 19.7$ balls

Thus we can conclude that approximately 20 balls can be filled in that can.

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