Answer:
The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average birth weight of babies was 7.5 pounds and the standard deviation was about 1.2 pounds.
This means that
Find the proportion of babies with birth weights of 6 pounds or less.
This is the pvalue of Z when X = 6. So
has a pvalue of 0.1056
The proportion of babies with birth weights of 6 pounds or less is 0.1056 = 10.56%.
Answer:
<92
Step-by-step explanation:
Supplementary angles add up to 180°.
180-88=92
∠88° is supplementary to <92.
Answer:
4
Step-by-step explanation:
Answer: 68.18% and 90.91%
Step-by-step explanation:
Deb is searching for airline tickets. Two weeks ago, the cost to fly from Orlando to Denver was $220 while the cost now is $370.
Price two weeks ago= $220
Price as at today= $370
Increase in price =$370-$220=$150
Percentage increase= 150/ 220 × 100
=0.6818 × 100 = 68.18%
If the airline charges $50 fee for baggage with the new ticket price, the total cost will now be
$370 + $50= $420
Increase= $420 - $220 = $200
Percentage increase:
200/220 × 100
= 0.9091 × 100
= 90.91%