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vesna_86 [32]
2 years ago
5

Heehehehehhehehheheheheheehe ehe he e

Mathematics
1 answer:
saw5 [17]2 years ago
5 0

Answer:

8 batches

Step-by-step explanation:

divide 5 1/3 and 2/3

Hope this helps

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Quiana took out a loan to pay for a new car initially she owed the lender 15,234.68. she has repaid 247.43 of the loan each mont
mario62 [17]

Given Information:

Initial amount of loan = $15,234.68

Monthly payment = $247.43

Number of months = 5

Required Information:

Net change in loan = ?

Answer:

Net change in loan = $1,237.15 = $1,237(3/20)

Step-by-step explanation:

Quiana owed her lender an amount of 15,234.68 initially, she repaid the lender each month with an amount of $247.43 for 5 months, so the total amount that she repaid is

Total amount repaid = Monthly payment*Number of months

Total amount repaid = $247.43 × 5

Total amount repaid = $1,237.15

The remaining owed amount is given by

Balance = Initial amount of loan - Total amount repaid

Balance = $15,234.68 - $1237.15

Balance = $13,997.53

So the net change to the loan from Quiana's perspective over the past 5 months is,

Net change in loan = Initial amount of loan - Balance

Net change in loan = $15,234.68 - $13,997.53

Net change in loan = $1,237.15

or

Net change in loan = $1,237(3/20)

Therefore, the net change to the loan from Quiana's perspective over the past 5 months is $1,237.15

6 0
3 years ago
(-2,3) and (-2,1) what is the answer
Angelina_Jolie [31]
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pantera1 [17]

Answer:

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3 0
2 years ago
One month Kala rented 7 movies and 9 video games for a total of $85. The next month she rented 5 movies and 3 video games for a
hodyreva [135]
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3 years ago
If tan a = 9/40<br>use trigonometric identities to find the values of sin a and cos a.​
Sindrei [870]

Answer:

see explanation

Step-by-step explanation:

Given

tan a = \frac{9}{40} = \frac{opposite}{adjacent}

We require the hypotenuse h

Using Pythagoras' identity

h² = 9² + 40² = 81 + 1600 = 1681 ( take square root of both sides )

h = \sqrt{1681} = 41 , thus

sin a = \frac{opposite}{hypotenuse} = \frac{9}{41}

cos a = \frac{adjacent}{hypotenuse} = \frac{40}{41}

4 0
3 years ago
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