If (x + 2) is a factor of x3 − 6x2 + kx + 10, k

Mathematics

2 answers:

kherson [118]3 years ago

4 0

Answer:

k = -11

Step-by-step explanation:

Let $p(x) = x^3-6x^2+kx+10$

And x+2 is a factor of p(x)

Let x+2 = 0 => x = -2

Putting in p(x)

=> p(-2) = $(-2)^3-6(-2)^2+k(-2)+10$

By remainder theorem, Remainder will be zero

=> 0 = -8-6(4)-2k+10

=> 0 = -8-24+10-2k

=> 0 = -22-2k

=> -2k = 22

Dividing both sides by -2

=> k = -11

Tatiana [17]3 years ago

3 0

K=-11 for the answer

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