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Soloha48 [4]
3 years ago
7

Can some one help me please

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

x+2+10 is 13 which is the beginning of the perimeter

PilotLPTM [1.2K]3 years ago
6 0
I think it’s B I’m not for sure
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Buses on your route run every 11 minutes from 7 AM to 11 AM arrive at the bus stop at 8:18 AM how long will you wait for a bus
Vlada [557]
Your sentence is not complete.  Please proofread your questions before sharing them.  

I think you meant:
 
"<span>Buses on your route run every 11 minutes from 7 AM to 11 AM.  YOU arrive at the bus stop at 8:18 AM how long will you HAVE TO wait for a bus?"

Let's try this:

First bus arrives at 7 a.m.  The next one arrives at 7:11, the next at 7:22, the next at 7:33, the next at 7:44, the next at 7:55, the next at 8:06, the next at 8:17, and the next at 8:28.  You'll have to wait 10 minutes for the 8:28 bus.</span>
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valentina_108 [34]
@@ I come here to want to hear the answer
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3 years ago
X^2+6x-19=0 pls helpppp
USPshnik [31]

Answer:

Step-by-step explanation:

Since this is not factorable, let's just complete the square:

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8 0
3 years ago
Could someone help me? the video doenst explain it
True [87]

Personally, I would recommend reading this as a fraction, and splitting up mantissa from the power of 10. (Mantissa refers to the number 1.23 in 1.23\times10^n.)

\left(3.6 \times 10^{-5}\right) \div \left(9 \times 10^{-7}\right) = \dfrac{3.6 \times 10^{-5}}{9 \times 10^{-7}} = \dfrac{3.6}9 \times \dfrac{10^{-5}}{10^{-7}}

Now just reduce each fraction:

\dfrac{3.6}9 = \dfrac{36}{90} = \dfrac25 = 0.4

\dfrac{10^{-5}}{10^{-7}} = 10^{-5-(-7)} = 10^{-5+7} = 10^2

So

\left(3.6 \times 10^{-5}\right) \div \left(9 \times 10^{-7}\right) = 0.4 \times 10^2 = \boxed{4 \times 10^1}

since 0.4\times10^2 = 0.4 \times 100 = 40 = 4 \times 10.

7 0
3 years ago
Write the word names for each of the numerals in the following paragraph. One popular fast-food chain ordered (a) 2,400,000 slic
Andrej [43]
A) two million four hundred thousand 
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4 years ago
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