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mote1985 [20]
3 years ago
10

X^2+6x-19=0 pls helpppp

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Since this is not factorable, let's just complete the square:

x^2+6x=19\\x^2+6x+9=28\\(x+3)^2=28\\x+3=\sqrt{28}\\x=2\sqrt{7}-3

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Answer:

See solution below.

Step-by-step explanation:

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3 years ago
The length of one base of a trapezoid is 44, the median is 36, and the other base is 2x + 10.
Nataliya [291]

Answer:

The answer is "9"

Step-by-step explanation:

Given value:

length of trapezoid = 44

Another length = 2x+10

median = 36

formula:

median =(first length + second length) /2

36 = \frac{(44+  2x+10)}{2}\\\\ 36 = \frac{54+2x}{2}\\\\36 \times 2 = 54 +2x\\\\72 =54 +2x\\\\2x= 72-54\\\\2x= 18\\\\x= 9

6 0
3 years ago
Find the midpoint between (-1+9i) and B=(5-3i)
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Answer:

2 + 3i, midpoint is (2,3)

Step-by-step explanation:

we need to find the midpoint between (-1+9i) and B=(5-3i)

To find the midpoint of two points (a+bi)  and (c+di) in a complex plane,  

we apply formula

\frac{a+c}{2} + \frac{b+d}{2} i

A = (-1+9i) and B=(5-3i)

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8 0
3 years ago
Read 2 more answers
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Answer:

A- X= 20÷5-3

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Step-by-step explanation:

Okay, well we have to work backwards. 20 cookies, and she makes 5 bags. We need to find out what 'x' means. To do that, we take 20 cookies and divide it by 5. 4 cookies. Then we want to take 3 cookies out of each bag to find out how many cookies she first put in. 1 cookie.

Let's check:

bag 1:

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bag 2:

o (one cookie)

bag 3:

o (one cookie)

bag 4:

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bag 5:

o (one cookie)

Now we have 15 cookies left. Now let's put 3 in each:

bag 1:

o (one cookie)

v v v ( three cookies)

bag 2:

o (one cookie)

v v v ( three cookies)

bag 3:

o (one cookie)

v v v ( three cookies)

bag 4:

o (one cookie)

v v v ( three cookies)

bag 5:

o (one cookie)

v v v ( three cookies)

Now we have no cookies left, and we put 4 cookies in each. (o representing the first cookie, v representing the next three cookies)

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Is BA(OH)2 soluble or insoluble in water
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